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zloy xaker [14]
2 years ago
7

The point (1, −1) is on the terminal side of angle θ, in standard position. What are the values of sine, cosine, and tangent of

θ? Make sure to show all work.
Mathematics
1 answer:
defon2 years ago
7 0
The abscissa of the ordered pair, that is the x-coordinate, is equal to 1 and the ordinate, the y-coordinate, is equal to -1. In the cartesian plane, this point lies in the fourth (IV) quadrant. The standard position of the angle is that which has one of its side is in the x-axis.

Solve for the hypotenuse of the right triangle formed.
           h = sqrt((-1)² + (1)²) = √2
Below items show the calculation for each of the trigonometric functions.

 sin θ = opposite/hypotenuse = y/h = (-1)/(√2) = -√2/2
 cos  θ = adjacent/hypotenuse = x/h = (1)/√2 = √2/2
tan θ = opposite/adjacent = y/x = -1/1 = -1
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Answer:

i dont know maybe you should search google. best of Luck

Step-by-step explanation:

4 0
2 years ago
What is the value of y?
kirill115 [55]
We are going to need more contex to awnser this
5 0
2 years ago
Which table does NOT represent a linear function?
chubhunter [2.5K]

Hey there!
Linear functions have a continuous change.

Let's check these tables and see if we can tell linear functions from non-linear functions.

The first one is

  • x values: -1, 0, 1, 2

- we add 1 each time

  • y values: 8, 5, 2, -1

- we subtract 3 each time

\rule{200}{2}

Let's try the next one:

  • x values: -1, 0, 1, 2

- we add 1 each time

  • y values: 5, 10, 15, 20

- we add 5 each time

\rule{200}{2}

Let's try the third one:

  • x values: -1, 0, 1, 2
  • - we add 1 each time
  • y values: 15, 18, 20, 21

        - we add 3, then 2, then 1..

So this table doesn't represent a linear function.

Let's check the fourth one:

  • x values: -1, 0, 1, 2

- we add 1 each time

  • y values: 1, 2, 3, 4

- we add 1 each time

Thus, Option C is the right option.

Hope everything is clear.

Let me know if you have any questions!

Always remember: Knowledge is power!

4 0
2 years ago
When two fair dice are rolled, what is the probability that at least one of the numbers will be even??
netineya [11]
The probability would be 1/4. The probability of rolling an even number on each die is 1/2. Since there are two dice you would multiply the probability of each die together. 1/2*1/2=1/4. The reason you would this is because you could roll two odd numbers that equal an even number such as 3 and 5.
4 0
3 years ago
What is the solution to the system? 1. x-y + 2 z = -7<br> 2. y + z =1<br> 3. x-2 y - 3 z = 0
kvv77 [185]

You'd find this problem easier to understand and do if you'd please list the defining equations vertically and line up variables:

1. x - 1y + 2 z = -7

2. y + 1z = 1

3. x - 2 y - 3 z = 0 Now eliminate the line numbers:

x - 1y + 2 z = -7

1y + 1 z = 1

x - 2 y - 3 z = 0

Let's use the elimination method to eliminate variable z: Seeing that z = 1 - y, we transform the first equation into 1x - 1y + 2(1-y) = -7

and the third into x - 2y - 3(1-y) = 0.

Simplifying 1x - 1y + 2(1-y) = -7

and x - 2y - 3(1-y) = 0,

we get

1x - 2y - 3 + 3y) = 0 and 1x - 1y + 2 - 2y = -7

which in turn simplify to

1x + y = 3 and 1x - 3y = -9

Having eliminated the variable z, we now focus on eliminating x. Mult. the 1st equation by -1, obtaining -1x - 1y = -3. Add this result to 1x - 3y = -9:

0 - 4y = -12, which tells us that y = 3. Subbing 3 for y in 1x + 1y = 3 tells us that x = 0.

All we have left to determine is the vaue of z.

Borrowing Equation 3, from above, we get x - 2 y - 3 z = 0, and into this equation we substitute x = 0 and y = 3: 0 -2(3) - 3z = 0.

Thus, -3z = 6, and z = -2.

The solution set is (0, 3, -2). You should check this by substitution.

3 0
3 years ago
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