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zloy xaker [14]
3 years ago
7

The point (1, −1) is on the terminal side of angle θ, in standard position. What are the values of sine, cosine, and tangent of

θ? Make sure to show all work.
Mathematics
1 answer:
defon3 years ago
7 0
The abscissa of the ordered pair, that is the x-coordinate, is equal to 1 and the ordinate, the y-coordinate, is equal to -1. In the cartesian plane, this point lies in the fourth (IV) quadrant. The standard position of the angle is that which has one of its side is in the x-axis.

Solve for the hypotenuse of the right triangle formed.
           h = sqrt((-1)² + (1)²) = √2
Below items show the calculation for each of the trigonometric functions.

 sin θ = opposite/hypotenuse = y/h = (-1)/(√2) = -√2/2
 cos  θ = adjacent/hypotenuse = x/h = (1)/√2 = √2/2
tan θ = opposite/adjacent = y/x = -1/1 = -1
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Given Sn=2n^2 - 5n, find
brilliants [131]

Answer:

a) -3

b) 117

c) 100

Step-by-step explanation:

(a) 2(1)²-5(1)

1²= 1

2×1= 2

2-5= -3

(b) 2(9)²-5(9)

9²= 81

81×2= 162

162-45= 117

(c) 2(4)²-5(4) +2(8)²-5(4)

4²=16

16×2= 32

32-20= 12

8²=64

64×2= 128

128-40= 88

88+12= 100

hope it helps!

6 0
3 years ago
Help me please, it dues by monday
Lera25 [3.4K]
The equation that you must use is y=15x+15
so x would be 1,2,3,4,5 and y would be 30,45,60,75,90
8 0
3 years ago
I need help on thiss​
Ratling [72]
B because it is between x: 4 and 6. And it is linear and decreasing
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Solve the equation using the Zero-Product Property (X-9)(x+7)=0
aleksandr82 [10.1K]
(x-9)(x+7)=0
x-9=0 or x+7=0
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:)
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