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Zepler [3.9K]
3 years ago
7

Show the steps on solving

Mathematics
1 answer:
inna [77]3 years ago
3 0
0.3(12x-16) = 0.4(12-3x)
0.3 is easier written as 3/10 and 0.4 easier written as 2/5, but in this case, 4/10 would help with the other fractions

3*12x/10-16*3/10 = 12*4/10 - 3x*4/10

36x/10-48/10 = 48/10 - 12x/10

since all the fractions are divided by 10, you can remove them totally by multiplying everything with 10

36x-48 = 48 - 12x

36x + 12x = 48 + 48

Here we moved the numbers, by adding them to both sides

48x = 48*2
we can find x by dividing by 48

x = 48*2/48
since we have a 48 both over and under the fraction we can cross out both

x = 2/1 = 2
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ANTONII [103]

Answer:

C, ON/MN

Step-by-step explanation:

Since tan is opposite/adjacent, and the opposite of angle M is NO, then NO must be the numerator. The only answer with this as the numerator is C.

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Slav-nsk [51]

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Help me please <br> !!!!!!!!!!!!
Tpy6a [65]

Answer:

40

Step-by-step explanation:

Angle Formed by Tangent and Secant = 1/2 (DIFFERENCE of Intercepted Arcs)

< WVT = 1/2 ( WT - UW)

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Distribute

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Combine like terms

3x+4    = 1/2 ( 7x -4 )

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Answer:

Correct option is

b. If two sides and one included angle are equal in triangles PQS and PRS, then their corresponding sides are also equal.

Step-by-step explanation:

Here, we are given the line RQ, which is divided in two equal parts by a line PS which is perpendicular to RQ.

The foot S of PS is on the line RQ.

First of all, let us do a construction here.

Join the point R with P and P with Q.

Please refer to the attached image.

Now, let us consider the triangles  PQS and PRS:

  • Side QS = RS (as given)
  • \angle PSR = \angle PSQ = 90^\circ
  • Side PS = PS (Common side in both the triangles)

Now, Two sides and the angle included between the two triangles are equal.

So by SAS congruence we can say that \triangle PRS \cong \triangle PQS

Therefore, the corresponding sides will also be equal.

RP = QP

RP is the distance between R and P.

QP is the distance between Q and P.

Hence, to prove that P is equidistant from R and Q, we have proved that:

b. If two sides and one included angle are equal in triangles PQS and PRS, then their corresponding sides are also equal.

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Dennis_Churaev [7]

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