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EastWind [94]
3 years ago
13

What is four points fewer than the bulls scored write in a algebraic expression

Mathematics
2 answers:
aleksandrvk [35]3 years ago
5 0
Your Algebraic expression could be X=b-4
Elena-2011 [213]3 years ago
4 0
B - 4   where B is the variable representing the Bulls score
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15 points to answer this question
Mamont248 [21]

it is none since there is no relation

4 0
3 years ago
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Find the length and width of a rectangle that has the given perimeter and a maximum area. perimeter: 244 meters
MissTica
We know that

[perimeter of rectangle]=2*(<span>length+width)
</span>
Let
x-----------> length
y-----------> width
so
P=2*(x+y)-----------> 244=2*(x+y)-----> x+y=122-------> y=122-x

Area=x*y-------> x*(122-x)----> 122x-x²

find the derivative function and equals to zero

122-2x=0-----> 122=2x----------> x=61 m
y=122-x------> y=122-61---------> y=61 m

<span>the maximum area is given by a square
</span>
the answer is
is a square of side 61 m


6 0
3 years ago
IF CORRECT ILL MARK U BRAINLIEST❤️
natulia [17]

Answer:

Step-by-step explanation:

y/x = 12/4 = 3

5 0
3 years ago
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What’s 0.85 in simplest form
jek_recluse [69]

Answer:

17/20

Step-by-step explanation:

To find the simplest form of 0.85 you need to turn it into a fraction.

To turn it into a fraction you put 85 over 100 since 0.85 is in the hundredths place.

85/100 can be simplified to 17/20 because 85/5 is 17 and 100/5 is 20

5 0
3 years ago
What is the kinetic Energy of a 110 kg linebacker rushing towards his football
Leviafan [203]

<u>Answer:</u>

The Kinetic energy of the 110 kg linebacker is 1375 J

<u>Solution:</u>

The kinetic energy of an object is the energy produced by its velocity. Kinetic energy of an object is directly proportional to the mass and the square of the its velocity.

Therefore, the formula for kinetic energy is

KE=\frac{1}{2} \times m v^{2}

Here, The linebacker’s mass m = 110 kg

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So by substituting the values,

The kinetic energy of linebacker is

K E=\left(\frac{1}{2} \times 110 \times 5 \times 5\right) \text { Joules } \\\\ \Rightarrow (\frac{2750}{2}) Joules = 1375 Joules

3 0
3 years ago
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