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USPshnik [31]
3 years ago
15

Please help, I need the answer ASAP! This is timed... Which expression is equivalent to 3x^-6y^-3 / 15x^2y^10 ? Assume x≠0, y≠0.

Mathematics
2 answers:
Ket [755]3 years ago
7 0

Answer:

1/(5x^8y^13)

Step-by-step explanation:

To simplify this exponential expression we must use some of the laws of exponents, specifically the quotient law.  The quotient law states that if the base is the same and you're dividing we subtract the exponents and so: \frac{a^m}{a^n}= a^{m-n}

Therefore:

\frac{3x^{-6}y^{-3}}{15x^2y^{10}} =\frac{x^{-6-2}y^{-3-10}}{5}=\frac{x^{-8}y^{-13}}{5}\\  \\\frac{1}{5x^8y^{13}}


Yakvenalex [24]3 years ago
3 0

Answer:

b

Step-by-step explanation:

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Andrei [34K]

Answer:

a gas in a rigid container has a pressure of 632 torrs and a temperature of 45 celsius. The pressure has increased to 842 torrs. What is the new temperature of the gas

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Find the volume of the prism.<br> 83 m<br> 7 m<br> 4 m
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167 is the volume of the prism
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The manager of a fleet of automobiles is testing two brands of radial tires and assigns one tire of each brand at random to the
Darya [45]

Answer:

Brand 1    Brand 2    Difference

37734       35202        2532

45299      41635         3664

36240      35500        740

32100      31950         150

37210       38015       −805

48360     47800        560

38200    37810          390

33500    33215        285

Sum of difference = 2532+ 3664+740+150 −805+  560 +390 +285 = 7516

Mean = d=\frac{7516}{8}

Mean = d=939.5

a) d= 939.5

\text{Sample Standard deviation, s} = \sqrt{\dfrac{(x-\bar{x})^2}{n-1}}

=\sqrt{\dfrac{(2532-939.5)^2+(3664-939.5)^2+(740-939.5)^2 ...+(285-939.5)^2}{8-1}}

=1441.21

b)SD= 1441.21

c)Calculate a 99% two-sided confidence interval on the difference in mean life.

confidence level =99%

significance level =α= 0.01

Degree of freedom = n-1 = 8-1 =7

So, t_{\frac{\alpha}{2}}=3.499

Formula for confidence interval = \left( \bar{X} \pm t_{\frac{\alpha}{2}} \times \frac{s}{\sqrt{n}} \right)

Substitute the values

confidence interval = 939.5 \pm 3.499 \times \frac{1441.21}{\sqrt{8}} \right)

confidence interval = 939.5 - 3.499 \times \frac{1441.21}{\sqrt{8}} \right) to  = 939.5 + 3.499 \times \frac{1441.21}{\sqrt{8}} \right)

Confidence interval −843.396\ to  2722.396

8 0
3 years ago
The sum of two numbers is 51 and the greater number is twice the smaller number. Find the numbers. a) set up the variables Let _
Gelneren [198K]

Answer:

  • 34 and 17

Step-by-step explanation:

a) set up the variables

Let x represent the first number Then  y will represent the second number.

b) What is the equation that represents the above situation?

  • x = 2y
  • x + y = 51

c) Solve the equation.

<u>Substitute x in the second equation and solve for y:</u>

  • x + y = 51
  • 2y + y = 51
  • 3y = 51
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<u>Then find x</u>

  • x = 2y = 2*17 = 34
4 0
3 years ago
Read 2 more answers
1.Find n. 2. Find n. 3.Find n. 4.Find n. <br> 2/9 = 14/n 12/18 = n/36 30/38 = 15/n 60/66 = n/22
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Step-by-step explanation:

cross multiply all equations seperately

1,n=63

2.n=24

3.n=19

4.n=20

7 0
3 years ago
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