Question

Factor completely 4x^4-20x^3+12x^2

Answer 1

Answer:

With integers: 4x^2 (x^2-5x+3)

After quadratic:

Step-by-step explanation:

First, find the Greatest Common Factor of all the terms:

$4 {x}^{2}$

Now factor it out of each term:

$4 {x}^{2} ( {x}^{2} - 5x + 3)$

All I did was I took each term and put it over my GCF.

$4 {x}^{4} \div 4 {x}^{2} = {x}^{2} \\ - 20 {x}^{3} \div 4 {x}^{2} = - 5x \\ 12 {x}^{2} \div 4 {x}^{2} = + 3$

Unfortunately it cannot factor nicely any further, if you want the full answer, plug "x^2-5x+3" into the quadratic formula "x=(-b+/-sqrt (b^2-4ac))/(2a).