20 it the least common multiple of the numbers given
3500(1 + .03/12)^12(5)
3500(1.0025)^60
The answer is:
$4,065.66 or $4,066
Hope this helps :)
1. 4x - 8 + 2x + (-5x) + x^2 - 3 = 4x - 8 + 2x - 5x + x^2 - 3...now, we just combine like terms....lets group them...it will be easier ...x^2 + (4x + 2x - 5x ) - 8 - 3 = x^2 + x - 11
2. 2x + 5x = 8x
3. 2r + 4 + 3x - 2 = 3x + 2r + (4 - 2) = 3x + 2r + 2
4. 3x - 2y - x + 5y = (3x - x) + (5y - 2y) = 2x + 3y
5. 2y^2 - 8y^3 + 5y - 5y^2 + 4y^3 = (4y^3 - 8y^3) + (2y^2 - 5y^2) + 5y =
-4y^3 - 3y^2 + 5y
Answer:
1st question: M=22.62 while C=75.38
2nd question: M=.22 while C=1.97
Step-by-step explanation:
If a mirror costing x dollars is marked up 30%, then we have to find x such that 30%x+x is 98 dollars.
We are solving:
.3x+x=98
Combine like terms:
1.3x=98
Divide both sides by 1.3:
x=75.38
M=98-75.38=22.62
C=75.38
So M=22.62 while C=75.38.
If ream of paper cost x and is marked up 11%, then we have to find x such that 11%x+x is 2.19.
We are solving:
.11x+x=2.19
1.11x=2.19
x=1 97
M=2.19-1.97=.22
So M=.22 while C=1.97
Plug -3 into the equation: w(-3)=14-6(-3)
simplify: w(-3)=14+18
solve: w(-3)=32