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BARSIC [14]
3 years ago
15

An angle measures 14° less than the measure of its complementary angle. What is the measure of each angle?

Mathematics
2 answers:
garri49 [273]3 years ago
8 0

Answer:

38 and 52

Step-by-step explanation:

x = small angle

Complementary angles add to 90 degrees

x + x+14 = 90

2x = 76

x= 38

90-38 = 52

52-14 = 38

38 +52 = 90

zmey [24]3 years ago
3 0
(180-14):2= 166:2= 83° (smaller angle)
(180-14):2+14= 166:2+14= 83+14= 97° (bigger angle)
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3 years ago
The Lakewood Wildcats won 5 out of their first seven games in this year. There are 28 games in the season. About how many games
allochka39001 [22]

Answer:

The total number of matches expected to be won by Lakewood Wildcats in this season  is 20.

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The number of games played by Lakewood Wildcats = 7

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3 years ago
A farmer has a field in the shape of a triangle. The farmer has asked the manufacturing class at your school to build a metal fe
Finger [1]

Answer:

<em>Fencing required = 1586 m</em>

Step-by-step explanation:

The given statements can be thought of a triangle \triangle ABC as shown in the diagram attached.

A be the 1st vertex, B be the 2nd vertex and C be the 3rd vertex.

Distance between 1st and 2nd vertex, AB = 435 m

Distance between 2nd and 3rd vertex, AC = 656 m

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To find:

Fencing required for the triangular field.

Solution:

Here, we know two sides of a triangle and the angle between them.

To find the fencing or perimeter of the triangle, we need the third side.

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cos A = \dfrac{b^{2}+c^{2}-a^{2}}{2bc}

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b is the side opposite to \angle B

c is the side opposite to \angle C

\Rightarrow cos 49^\circ = \dfrac{656^{2}+435^{2}-BC^{2}}{2\times 435\times 656}\\\Rightarrow BC^2 = 430336+189225-2 (435)(656)cos49^\circ\\\Rightarrow BC^2 = 430336+189225-570720\times cos49^\circ\\\Rightarrow BC^2 =619561-570720\times cos49^\circ\\\Rightarrow BC \approx 495\ m

Perimeter of the triangle = Sum of three sides = AB + BC + AC

Perimeter of the triangle = 435 + 495 + 656 = <em>1586 m</em>

<em></em>

<em>Fencing required = 1586 m</em>

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