Answer:
Step-by-step explanation:
∠AHE + ∠AHK = 180 {linear pair}
6x + 7 + 35 = 180
6x + 42 = 180
6x = 180 - 42
6x = 138
x = 138/6
x = 23
Answer:
m = 10
Step-by-step explanation:
The value of <em>m</em> that would make this equation true is <em>10</em>. To figure this out you must work the equation to combine like terms. To start, remember PEMDAS. You would begin with <em>1/2 (8m - 18) </em>and multiply both <em>8m </em>and <em>18 </em>by <em>1/2. </em>Because half of <em>8</em> is <em>4</em> and half of<em> 18</em> is <em>9</em>, your new equation would be <em>4m - 9 = 31. </em>From here you would add nine to both sides to finish combining like terms. The equation from this point should be <em>4m = 40.</em> To find the value of <em>m</em>, you then have to divide both sides by <em>4</em>, leading to the equation/solution of <em>m = 10.</em>
Answer:
The number of distinct arrangements is <em>12600</em><em>.</em>
Step-by-step explanation:
This is a permutation type of question and therefore the number of distinguishable permutations is:
n!/(n₁! n₂! n₃! ... nₓ!)
where
- n₁, n₂, n₃ ... is the number of arrangements for each object
- n is the number of objects
- nₓ is the number of arrangements for the last object
In this case
- n₁ is the identical copies of Hamlet
- n₂ is the identical copies of Macbeth
- n₃ is the identical copies of Romeo and Juliet
- nₓ = n₄ is the one copy of Midsummer's Night Dream
Therefore,
<em>Number of distinct arrangements = 10!/(4! × 3! × 2! × 1!)</em>
<em> = </em><em>12600 ways</em>
<em />
Thus, the number of distinct arrangements is <em>12600</em><em>.</em>
Answer: C
Step-by-step explanation:
