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4 years ago

In triangle abc, ab=90 in, bc=80 in, and angle b measures 50°. what is the approximate perimeter of the triangle?

1 answer:

8 0

You need to use the Law of Cosines:
AC² = AB² + BC² - 2·AB·BC·cos(b)

Therefore, you get:

AC = √(90² + 80² - 2·90·80·cos(50)
=√5243.86
= 72.4 in

Now you can sum up all the sides in order to find the perimeter:

AB + BC + AC = 90 + 80 + 72.4 = 242.4 in

The correct answer is A) 242.4 in

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Sam has 13 1/2 yards of ribbon. He cuts them 3/4 yards . What is the maximum numbers of pieces of ribbon

german

Answer:

18

Step-by-step explanation:

You basically have to do 13.5 divided by 0.75 (3/4) which equals 18

4 0

3 years ago

To find the quotient of 4 divided by 1/5, multiply 4 by 1/5 1/4 4 Or 5

alina1380 [7]

Answer:

Step-by-step explanation:

When dividing numbers by fractions, we can simply multiply the umber by the reciprocal of the decimal. So,

4 ÷ 1/5 = 4 × (reciprocal of 1/5)

A reciprocal of a number is the same number written under 1. aka, 1 divided by that number, which simply is flipping the numerator and denominator of a number.

So the reciprocal of 1/5 is 5/1 = 5.

So 4 ÷ 1/5 = 4 × 5.

So your answer is 5.

hope it was useful!!! ;)

5 0

4 years ago

Read 2 more answers

What is the surface area of the right cone below?

Nadusha1986 [10]

B) 72pie units squared

3 0

3 years ago

Find the volume of the square pyramid below.

miv72 [106K]

Hello!

$\bf ANSWER$

The volume of the square pyramid is approximately $\boxed{ \bf 19.19~km^3}$

____________________________________________________________

$\bf EXPLANATION$

V = $a^{2}$ $\frac{h}{3}$

First, we must find the area of the square base.

A = l * w

A = 3.5 * 3.5

A = 12.25 km^2

The area of the base is 12.25 km^2. Now, multiply the base area by the perpendicular height. Then divide by 3.

V = (12.25 * 4.7) / 3

V = 19.1916666667

V ≈ 19.19 km^3

7 0

4 years ago

Solving systems of equations using any method

andreev551 [17]

Answer:

x = 5 , y = 2

Step-by-step explanation:

Solve the following system:

{y = (7 x)/5 - 5 | (equation 1)

{y = (3 x)/5 - 1 | (equation 2)

Express the system in standard form:

{-(7 x)/5 + y = -5 | (equation 1)

{-(3 x)/5 + y = -1 | (equation 2)

Subtract 3/7 × (equation 1) from equation 2:

{-(7 x)/5 + y = -5 | (equation 1)

{0 x+(4 y)/7 = 8/7 | (equation 2)

Multiply equation 1 by 5:

{-(7 x) + 5 y = -25 | (equation 1)

{0 x+(4 y)/7 = 8/7 | (equation 2)

Multiply equation 2 by 7/4:

{-(7 x) + 5 y = -25 | (equation 1)

{0 x+y = 2 | (equation 2)

Subtract 5 × (equation 2) from equation 1:

{-(7 x)+0 y = -35 | (equation 1)

{0 x+y = 2 | (equation 2)

Divide equation 1 by -7:

{x+0 y = 5 | (equation 1)

{0 x+y = 2 | (equation 2)

Collect results:

Answer: {x = 5 , y = 2

7 0

3 years ago