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andreev551 [17]
3 years ago
5

Janet has three coins.

Mathematics
1 answer:
tatyana61 [14]3 years ago
8 0

Answer:

Janet has coins worth 252.5, 101, and 50.5.

Step-by-step explanation:

Let us call the three coins a,b, and c.

The first coin a is 5 times another coin<em> (let's say </em>b); therefore,

a = 5b,

and the third coin is 2 times the value of another coin<em> (it's coin </em>b<em>):</em>

<em />c =2b<em>.</em>

The total worth of all coins is 404; therefore,

a+b+c =404

or

5b+b+2b =404

8b =404

\boxed{b = 50.5}

with the value of b in hand, we find a and c:

a = 5b = 5(50.5)

\boxed{a = 252.5}

and for c:

c = 2 b = 2 (50.5)

\boxed{c = 101}

Thus, Janet has 3 coins worth 252.5, 101, and 50.5.

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