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3 years ago

IS (1, 2) of a solution set of x+ y = 3 and 2 x + 7 y = 16 ?

Mathematics

1 answer:

Brilliant_brown [7]3 years ago

6 0

Answer:

yes

Step-by-step explanation:

x=3-y

2(3-y)+7y=16

6-2y+7y=16

5y=10

y=2

x=3-2=1

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PLEASE HELP!!!

Pachacha [2.7K]

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2. JK -1-2/4+3
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5 0

3 years ago

Bryan wants to convert a speed of 85 kilometers per hour into the speed in meters per second what is the correct conversion

lara31 [8.8K]

Answer:

23.6111

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Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

How many terms are there in the sequence 1, 8, 28, 56, ..., 1 ?

BabaBlast [244]

Answer:

9 terms

Step-by-step explanation:

Given:

1, 8, 28, 56, ..., 1

Required

Determine the number of sequence

To determine the number of sequence, we need to understand how the sequence are generated

The sequence are generated using

$\left[\begin{array}{c}n&&r\end{array}\right] = \frac{n!}{(n-r)!r!}$

Where n = 8 and r = 0,1....8

When r = 0

$\left[\begin{array}{c}8&&0\end{array}\right] = \frac{8!}{(8-0)!0!} = \frac{8!}{8!0!} = 1$

When r = 1

$\left[\begin{array}{c}8&&1\end{array}\right] = \frac{8!}{(8-1)!1!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8$

When r = 2

$\left[\begin{array}{c}8&&2\end{array}\right] = \frac{8!}{(8-2)!2!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} =2 8$

When r = 3

$\left[\begin{array}{c}8&&3\end{array}\right] = \frac{8!}{(8-3)!3!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56$

When r = 4

$\left[\begin{array}{c}8&&4\end{array}\right] = \frac{8!}{(8-4)!4!} = \frac{8!}{4!3!} = \frac{8 * 7 * 6 * 5 * 4!}{4! *4*3* 2 *1} = \frac{8 * 7 * 6*5}{4*3 *2 *1} = 70$

When r = 5

$\left[\begin{array}{c}8&&5\end{array}\right] = \frac{8!}{(8-5)!5!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56$

When r = 6

$\left[\begin{array}{c}8&&6\end{array}\right] = \frac{8!}{(8-6)!6!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} = 28$

When r = 7

$\left[\begin{array}{c}8&&7\end{array}\right] = \frac{8!}{(8-7)!7!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8$

When r = 8

$\left[\begin{array}{c}8&&8\end{array}\right] = \frac{8!}{(8-8)!8!} = \frac{8!}{8!0!} = 1$

The full sequence is: 1,8,28,56,70,56,28,8,1

And the number of terms is 9

3 0

3 years ago

How do you do question number 5? If you do it can you please explain how to do it? Thank you!!

erik [133]

F(-3) = 4(-3) - 3 = -12 - 3 = -15.
H(2) = -5(2) + 7 = -10 + 7 = -3.

F(-3) + H(2) = -15 + -3 = -18.

The solution is -18.

4 0

4 years ago

Read 2 more answers

A country’s population in 1993 was 94 million.

Wewaii [24]

Answer:

Step-by-step explanation:

A = Pe^rt

A = total

P = amount you start with

r = rate

t = time

Let's calculate the rate.

99000000 = 94000000e^r*6

Divide each side by 94m

99000000/94000000 = e^6r

Take the natural log of e of both sides.

ln(99000000/94000000) = 6r

Divide each side by 6.

(ln(99000000/94000000))/6 = r

Now we can find the population in 2005.

A = 94000000e^0.00863751131 * 12

A = 104265957

The population in 2005 is 104,265,957 people.

6 0

4 years ago

IS (1, 2) of a solution set of x+ y = 3 and 2 x + 7 y = 16 ?​

IS (1, 2) of a solution set of x+ y = 3 and 2 x + 7 y = 16 ?