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3 years ago

Estimate 2,244,000 to the nearest ten thousand

2 answers:

8 0

The answer to your problem is 2,200,000 because the 4 is not bigger than 5 so you won't be able to make it a bigger number and the rest turn to zeros.

aivan3 [116]3 years ago

4 0

It already is to its near east ten thousand.

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How many meters tall is a door

S_A_V [24]

Answer: a standard door is about 2-2.10 meters

Step-by-step explanation:

8 0

3 years ago

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Consider circle H with a 3 centimeter radius. If the length of minor arc RT is 2 3 π, what is the measure of ∠RST?

Nataliya [291]

The main formula is arc RT = r x measure RST
so ∠RST=minor arc RT / r
minor arc RT = 23π
r= 3 cm
∠RST= 23π/3

3 0

3 years ago

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Pls help and no links thankyou <3

Hitman42 [59]

Do the second one hope this helps

8 0

3 years ago

HELP!!!!

m_a_m_a [10]

Answer:

(0,0)

Step-by-step explanation:

The coordinates of C now are (-7,-5).

Moving C -3 on the x-axis will move -7 - 3 = -10. C is now located on (-10,-5).

Moving C +5 on the y-axis will move -5 + 5 = 0. C is now located on (-10,0).

Moving C on the y-axis +10 will move -10 + 10 = 0. C is now located on (0,0).

C is translated to (0,0).

8 0

3 years ago

Jason went to a carnival where he could goon all rides for a flat fee of $30 but he had to pay $2 for each arcade game he played

enot [183]

Answer:

He played 7 arcade games.

Step-by-step explanation:

The amount paid in relation to the number of games played can be modeled by a linear function in the following format:

$A(n) = F + gn$

In which F is the flat rate and g is the price of each game.

Flat fee of $30 but he had to pay $2 for each arcade game he played.

This means that $F = 30, g = 2$

$A(n) = 30 + 2n$

Jason spent $44. How many arcade games did he play?

This is n for which A(n) = 44. So

$A(n) = 30 + 2n$

$44 = 30 + 2n$

$2n = 14$

$n = \frac{14}{2}$

$n = 7$

He played 7 arcade games.

4 0

3 years ago