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MakcuM [25]
3 years ago
9

We have 938 employees across the country of which 533 provide customer service and the remaining employees provide sales support

?
41%, 43%, 45%, 47%, 50%
Mathematics
1 answer:
Otrada [13]3 years ago
7 0

Answer:

43%

Step-by-step explanation:

533 of 938 is 56.8 rounding to 57

100-57 is 43

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10. A moving van company charges a fee of 35.00 dollars for the truck rental and 25 cents for every mile the truck travels from
adelina 88 [10]

Answer:

y=0.25x+35

Step-by-step explanation:

if the truck doesn't have to travel at all, it costs $35 for the loading fee, so the y-intercept is (0, 35). As x increases by 1, y increases by 0.25, so the slope is 0.25. Therefore, the equation is y=0.25x+35

3 0
3 years ago
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A line passes through the points (1, –6) and (4, 3).
Ivanshal [37]

Answer:

y = - 9

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (1, - 6) and (x₂, y₂ ) = (4, 3)

m = \frac{3+6}{4-1} = \frac{9}{3} = 3

y = 3x + c ← is the partial equation

To find c substitute any of the 2 points into the partial equation

Using (4, 3), then

3 = 12 + c ⇒ c = 3 - 12 = - 9, hence

y- intercept c = - 9 ⇒ (0, - 9 )

8 0
3 years ago
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A large group of students took a test in Physics and the final grades have a mean of 70 and a standard deviation of 10. If we ca
Sholpan [36]

Answer:

The scores are between 50 and 90

Step-by-step explanation:

When we say middle 95%, we means that this value falls between 2 standard deviations of the mean i.e

μ ± 2σ

Hence,

mean of 70 and a standard deviation of 10

μ ± 2σ

μ - 2σ

70 - (2 × 10)

= 70 - 20

= 50

μ + 2σ

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= 70 + 20

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4 0
3 years ago
The overhead reach distances of adult females are normally distributed with a mean of 205 cm and a standard deviation of 8.3 cm.
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a. Find the probability that an individual distance is greater than 214.30 cm

We find for the value of z score using the formula:

z = (x – u) / s

z = (214.30 – 205) / 8.3

z = 1.12

Since we are looking for x > 214.30 cm, we use the right tailed test to find for P at z = 1.12 from the tables:

P = 0.1314

 

b. Find the probability that the mean for 20 randomly selected distances is greater than 202.80 cm

We find for the value of z score using the formula:

z = (x – u) / s

z = (202.80 – 205) / 8.3

z = -0.265

Since we are looking for x > 202.80 cm, we use the right tailed test to find for P at z = -0.265 from the tables:

P = 0.6045

 

c. Why can the normal distribution be used in part (b), even though the sample size does not exceed 30?

I believe this is because we are given the population standard deviation sigma rather than the sample standard deviation. So we can use the z test.

7 0
3 years ago
Michale has a loan with a balance of $200 at 14% simple interest. If he pays the loan back in 12 equal payments, how much will b
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Answer:

it would be 19 dollars a month

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