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noname [10]
2 years ago
8

Find the distance between ( - 10 , - 7 ) and ( - 8 , 1 ).

Mathematics
1 answer:
nevsk [136]2 years ago
8 0

Answer:

The distance point between (-10, -7) and (-8, 1) is 6

Step-by-step explanation:

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Find the quotient.<br><br> 35.4 ÷ 0.59
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Answer:

35.4÷ 0.59=60

Step-by-step explanation:

6 0
3 years ago
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What is the equation of a line through point (-4,5) that is perpendicular
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Answer:

set two equation of line y=ax+b and y=cx+d

when these two lines are perpendicular to each other, then a*c=(-1)

set answer is y=ax+b

we can know that a=1/6

bring in a=1/6 and(-4,5)

5=(1/6)*(-4)+b

=>5=(-2/3)=b

=>b=5 2/3

answer is y=(1/6)x+5 2/3

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In 2012, the population of Houston, Texas, was about 2 × 106 and the population of San Marcos, Texas, was about 5 × 104. Which o
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C

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2 years ago
The height of a fireworks rocket in meters can be approximated by h= -5t^2+30t, where h is the height in meters and t is the tim
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It takes 45 seconds. the easiest way to do these is to use a graphic calculator and replace the variables with x and y, for example, this equation would become -5x^2+30x, and if you don't have access to a graphing calculator, you can always use desmos online.

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2 years ago
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F(x)=2x^2-3x+7 evaluate f(-2)
Vilka [71]

Answer:

Step-by-step explanation:

Find two linear functions p(x) and q(x) such that (p (f(q(x)))) (x) = x^2 for any x is a member of R?

Let  p(x)=kpx+dp  and  q(x)=kqx+dq  than

f(q(x))=−2(kqx+dq)2+3(kqx+dq)−7=−2(kqx)2−4kqx−2d2q+3kqx+3dq−7=−2(kqx)2−kqx−2d2q+3dq−7  

p(f(q(x))=−2kp(kqx)2−kpkqx−2kpd2p+3kpdq−7  

(p(f(q(x)))(x)=−2kpk2qx3−kpkqx2−x(2kpd2p−3kpdq+7)  

So you want:

−2kpk2q=0  

and

kpkq=−1  

and

2kpd2p−3kpdq+7=0  

Now I amfraid this doesn’t work as  −2kpk2q=0  that either  kp  or  kq  is zero but than their product can’t be anything but  0  not  −1 .

Answer: there are no such linear functions.

6 0
2 years ago
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