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3 years ago

What's the answer this is equivalent fractions

Mathematics

1 answer:

IceJOKER [234]3 years ago

3 0

The answer is 3/4 because if u count it up it equals 36/48 and then u just have to simplify

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A number that is equal to x less than 80

krok68 [10]

Answer:

# = 80 - x

Step-by-step explanation:

You can't solve it :/ I don't think

I hope this helped

6 0

3 years ago

Starting with number 0 on my calculator, I do a calculation in five steps. At each step, I either add 1 or multiply by 2. What i

alisha [4.7K]

Answer:

assuming only positive integers, the answer is 1

Step-by-step explanation:

the smallest number that you can get by adding is:

start with 0
then add 1 = 1
add another 1 = 2
add another 1 = 3
add another 1 = 4
add another 1 = 5

but you can also multiply, and anything multiplied by 0 is 0:

start with 0
multiply by 2 = 0
multiply by 2 = 0
multiply by 2 = 0
multiply by 2 = 0
multiply by 2 = 0

The question does not say that we need to do any specific calculation, it only gives us 2 options and we can choose them as many times as we want.

5 0

3 years ago

Is y^24 a perfect cube

dlinn [17]

Y^24 isn't a cube, the closest number is 27

8 0

3 years ago

(THREE CAPITAL LETTERS FOR EACH) ANSWER CORRECTLY !!!!! WILL MARK BRIANLIEST !!!!!! URGENT !!!!!!!!!!

Natasha2012 [34]

FHG is congruent EFH

4 0

3 years ago

Define f(0,0) in a way that extends f to be continuous at the origin. f(x, y) = ln ( 19x^2 - x^2y^2 + 19 y^2/ x^2 + y^2) Let f (

kirill115 [55]

Answer:

f(0,0)=ln19

Step-by-step explanation:

$f(x,y)=ln(\frac{19x^2-x^2y^2+19y^2}{x^2+y^2})$ is given as continuous function, so there exist $lim_{(x,y)\rightarrow(0,0)}f(x,y)$ and it is equal to f(0,0).

Put x=rcosA annd y=rsinA

$f(r,A)=ln(\frac{19r^2cos^2A-r^2cos^2A*r^2sin^2A+19r^2sin^2A}{r^cos^2A+r^2sin^2A})=ln(\frac{19r^2(cos^2A+sin^2A)-r^4cos^2Asin^a}{r^2(cos^2A+sin^2A)})$

we know that $cos^2A+sin^2A=1$ , so we have that

$f(r,A))=ln(\frac{19r^2-r^4cos^2Asin^a}{r^2})=ln(19-r^2cos^2Asin^2A)$

$lim_{(x,y)\rightarrow(0,0)}f(x,y)=lim_{r\rightarrow0}f(r,A)=ln19$

So f(0,0)=ln19.

8 0

3 years ago