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Brrunno [24]
3 years ago
6

H(x) = -x^3-2x^2-3x+4; x=2

Mathematics
1 answer:
ioda3 years ago
4 0

Answer:

h(2)=-18

Step-by-step explanation:

h(x)=-x^3-2x^2-3x+4\\Substituting\ x=2,\\h(2)=-(2)^3-2(2)^2-3(2)+4\\h(2)=-(8)-2*4-6+4\\h(2)=-8-8-6+4\\h(2)=-22+4\\h(2)=-18

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</span>
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=========================================================

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