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3 years ago

H(x) = -x^3-2x^2-3x+4; x=2

Mathematics

1 answer:

ioda3 years ago

4 0

Answer:

h(2)=-18

Step-by-step explanation:

$h(x)=-x^3-2x^2-3x+4\\Substituting\ x=2,\\h(2)=-(2)^3-2(2)^2-3(2)+4\\h(2)=-(8)-2*4-6+4\\h(2)=-8-8-6+4\\h(2)=-22+4\\h(2)=-18$

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3 years ago

A total of $7000 is invested: part at 8% and the remainder at 12%. How much is invested at each rate if the annual interest is $

Ivahew [28]

We invested $7000 invested in two accounts, we don't know how much exactly is in each account, therefore we will assign variables to these amounts. The amount invested in the "8%" account is "x", while the other one is "y". The sum of these two numbers must be equal to $7000, therefore:

$x+y=7000$

The sum of interest of each account should be equal to 580, therefore:

$0.08\cdot x+0.12\cdot y=580$

We need to solve the system in order to determine the values.

$\begin{gathered} \begin{cases}x+y=7000 \\ 0.08x+0.12y=580\end{cases} \\ \begin{cases}-0.12x-0.12y=-840 \\ 0.08x+0.12y=580\end{cases} \\ -0.04x=-260 \\ x=\frac{-260}{-0.04}=6500 \\ \end{gathered}$

Now we can replace the value of "x" in the first equation to determine the value of "y".

$\begin{gathered} 6500+y=7000 \\ y=7000-6500 \\ y=500 \end{gathered}$

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1 year ago

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Nookie1986 [14]

52488 because 9 times 9 is 81, 81 times 9 equals 729, 729 times 9 equals 6561. 6561 x 8 = 52488

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3 years ago