H(x) = -x^3-2x^2-3x+4; x=2

Mathematics

1 answer:

ioda3 years ago

4 0

Answer:

h(2)=-18

Step-by-step explanation:

$h(x)=-x^3-2x^2-3x+4\\Substituting\ x=2,\\h(2)=-(2)^3-2(2)^2-3(2)+4\\h(2)=-(8)-2*4-6+4\\h(2)=-8-8-6+4\\h(2)=-22+4\\h(2)=-18$

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