3 years ago

H(x) = -x^3-2x^2-3x+4; x=2

Mathematics

1 answer:

ioda3 years ago

4 0

Answer:

h(2)=-18

Step-by-step explanation:

$h(x)=-x^3-2x^2-3x+4\\Substituting\ x=2,\\h(2)=-(2)^3-2(2)^2-3(2)+4\\h(2)=-(8)-2*4-6+4\\h(2)=-8-8-6+4\\h(2)=-22+4\\h(2)=-18$

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mihalych1998 [28]

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y = 4.125x + 496.25

Step-by-step explanation:

Set the data up as points. Then deal with the points.

Givens

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(70,785)

y2 = 785

y1 = 620

x2 = 70

x1 = 30

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Slope = (y2 - y1) / (x2 - x1)

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===================

Now you need the y intercept. Either one of the two given points will give you that.

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