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dalvyx [7]
3 years ago
13

Three students collected more than $93 washing cars. They used $15 to reimburse their parents for cleaning supplies. Then they d

ivided the remaining money equally. How much did each student earn?
Mathematics
2 answers:
shusha [124]3 years ago
5 0
Your answer is 26$, bcuz if u subtract 95 by 15 and divided by 3, u will find ur answer
Alenkasestr [34]3 years ago
4 0
First step is find profit so lets subtract 93 and 15.
93-15=78
Finally we can divide profit by 3 students, so
78:3=26$ its the answer
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Factor completely 2x2 − 50.
Ede4ka [16]

Answer:

(B) 2(x+5)(x−5)

Explanation:

Factor 2x²−50

2(x+5)(x−5)

3 0
3 years ago
Read 2 more answers
Please solve with working much appreciated
mojhsa [17]

Answer:

x°= 55°

Step-by-step explanation:

First, find the degrees of the larger triangle.

Since every triangle equals 180° degrees, make an equation.

60°+90°+a°= 180°

Now, add the degrees together.

120°+a°= 180°

Then subtract from both sides.

120°+a°= 180°

-120 °      -120°

a°= 60°

Now that you know the sum of all the angles, subtract 25° from 60°(which is the measure of a).

60°-25°= 35°

Now that we have the measurement of the angle from the smaller triangle inside the larger one, make an equation.

35°+90°+x°= 180°

Then, add the degrees.

125°+x°= 180°

Subtract from both sides of the equation to get the answer for the variable.

125°+x°= 180°

-125°       -125°

x°= 55°

6 0
3 years ago
Can someone please help me
solniwko [45]
(-2,2) (8,2) (8,-2) (-2,-2)
7 0
3 years ago
5<br> Find x to the nearest tenth.<br> 18.7<br> 13<br> 19.3<br> NEXT QUESTION<br> © ASK FOR HELP
Iteru [2.4K]
Think it’s option 1.3
6 0
3 years ago
A soccer ball is kicked from 3 feet above the ground. the height,h, in feet of the ball after t seconds is given by the function
dexar [7]
Here's our equation.

h=-16t+64t+3

We want to find out when it returns to ground level (h = 0)

To find this out, we can plug in 0 and solve for t.

0 = -16t+64t+3 \\ 16t-64t-3=0 \\ use\ the\ quadratic\ formula\ \frac{-b\±\sqrt{b^2-4ac}}{2a}  \\ \frac{-(-64)\±\sqrt{(-64)^2-4(16)(-3)}}{2*16}  = \frac{64\±\sqrt{4096+192}}{32}

= \frac{64\±\sqrt{4288}}{32} = \frac{64\±8\sqrt{67}}{32} = \frac{8\±\sqrt{67}}{4} = \boxed{\frac{8+\sqrt{67}}{4}\ or\ 2-\frac{\sqrt{67}}{4}}

So the ball will return to the ground at the positive value of \boxed{\frac{8+\sqrt{67}}{4}} seconds.

What about the vertex? Simple! Since all parabolas are symmetrical, we can just take the average between our two answers from above to find t at the vertex and then plug it in to find h!

\frac{1}2(\frac{8+\sqrt{67}}{4}+2-\frac{\sqrt{67}}{4}) = \frac{1}2(2+\frac{\sqrt{67}}{4}+2-\frac{\sqrt{67}}{4}) = \frac{1}2(4) = 2

h=-16t^2+64t+3 \\ h=-16(2)^2+64(2)+3 \\ \boxed{h=67}


8 0
3 years ago
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