Using V = ⅓[base area×height]
V= ⅓[ (5.5÷4)² × 2.6]
v= ⅓[ 4.92]
v = 1.6m³
We are give the equation of the perimeter of the triangle as follows:
2a + b = 15.7
where b represents the base.
Now, if we want to calculate the length of the base, all we have to do is isolate the b in one side of the equation as follows:
b = 15.7 - 2a
We know that a = 6.3 cm, therefore, the length of the base can be calculated as follows:
b = 15.7 - 2(6.3) = 3.1 cm
The question is an illustration of bearing (i.e. angles) and distance (i.e. lengths)
The distance between both lighthouses is 5783.96 m
I've added an attachment that represents the scenario.
From the attachment, we have:

Convert to degrees





Convert to degrees



So, the measure of angle S is:
---- Sum of angles in a triangle


The required distance is distance AB
This is calculated using the following sine formula:

Where:

So, we have:

Make AB the subject


Hence, the distance between both lighthouses is 5783.96 m
Read more about bearing and distance at:
brainly.com/question/19017345
The correct answer is False.
Because each input must only have one output.
But an output can have more than one input.
Hope This helps!!!
Answer:The roots are:

and
Explanation:First, we will need to expand the bracket on the left and then put teh equation i standard form which is:
ax² + bx + c = 0
This can be done as follows:
(x+5)² = 10
(x)² + 2(x)(5) + (5)² = 10
x² + 10x + 25 - 10 = 0
x² + 10x + 15 = 0
By comparison, we can find that:
a = 1
b = 10
c = 15
Now to get the roots, we would need to use the quadratic formula shown in the attached image.
By substitution, we would find that:
either x =

or x =

Hope this helps :)