A = 11300 cm<span>2
</span>
Hope this helps!
You can work these in your head if you consider the revenue generated by the least contributor (children's tickets) and the difference in revenue between that and the larger contributor ($2.00 -1.50 = 0.50).
If all were children's tickets, the revenue would be 500*$1.50 = $750.00. The actual revenue exceeded that amount by $862.50 -750.00 = 112.50. This difference in revenue is made up by the sale of $112.50/$0.50 = 225 adult tickets. Then the number of children's tickets is 500 -225 = 275.
225 adult tickets were sold
275 children's tickets were sold.
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If you need an equation, you can write an equation using a variable for the number of adult tickets sold (the largest contributor).
.. (500 -a)*1.50 +a*2.00 = 862.50
.. 0.50a = (862.50 -750.00) . . . . . does this look familiar, yet?
.. a = 112.50/0.50 = 225
Answer:
-5 - h
Step-by-step explanation:
ƒ(x) = 1 + 5x - x²
[f(5 + h) -f(5)]/h
= [1 + 5(5 + h) - (5 + h)² - 1 - 5(5) +5²]/h
= (25 + 5h - 25 - 10h - h² - 25 + 25)/h
= (-5h - h²)/h
= -5 - h
The difference quotient is -5 - h.
