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-BARSIC- [3]
3 years ago
7

What is the length of the tabletop

Mathematics
1 answer:
zzz [600]3 years ago
5 0
The table's length is 186 centimeters..........................
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Two equations are given below:
stealth61 [152]

a is given to us so just plug a into the first equation:

b-3 - 3b =9

Add 3 to both sides:

b-3b=12

Combine like terms:

-2b=12

Divide by -2 to get b by itself:

b=-6

The only answer with b as -6 is the first one, (-9,-6)

8 0
3 years ago
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Which table represents y as a function of x
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B the one u already have clicked

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2 years ago
5. Landon bought a new car for $16,000 and it depreciates 4.5% every year. Write a function that describes
snow_tiger [21]

Answer:

<h3>The value C(t) of the car after  5  years is $12709.</h3>

Step-by-step explanation:

Given that Landon bought a new car for $16,000 and it depreciates 4.5% every year.

<h3>To find the value C(t) of the car after  5  years:</h3>

Initial value C(0)= $16,000

Depreciation rate is  r=\frac{4.5}{100}

<h3>∴ r=0.045</h3>

Period ,  t=5 years

C(t)=C(0)(1-r)^t

Substitute the values we get

C(5)=16000(1-0.045)^5

=16000(0.955)^5

=16000(0.7943)

∴ C(5)=12708.8

<h3>The value C(t) of the car after  5  years is  $ 12709</h3>
3 0
2 years ago
work for a publishing company. The company wants to send two employees to a statistics conference. To be​ fair, the company deci
Yuki888 [10]

Answer:

(a) S = {MR, MJ, MD, MC, RJ, RD, RC, JD, JC, DC}

(b) The probability that Roberto and John attend the​ conference is 0.10.

(c) The probability that Clarice attends the​ conference is 0.40.

(d) The probability that John stays​ home is 0.60.

Step-by-step explanation:

It is provided that :

Marco (<em>M</em>), Roberto (<em>R</em>), John (<em>J</em>), Dominique (<em>D</em>) and Clarice (<em>C</em>) works for the company.

The company selects two employees randomly to attend a statistics conference.

(a)

There are 5 employees from which the company has to select two employees to send to the conference.

So the total number of ways to select two employees is:

{5\choose 2}=\frac{5!}{2!(5-2)!}=\frac{5\times 4\times 3!}{2\times 3!}=10

The 10 possible samples are:

MR, MJ, MD, MC, RJ, RD, RC, JD, JC, DC

(b)

The probability of the event <em>E</em> is:

P(E)=\frac{n(E)}{N}

Here,

n (E) = favorable outcomes

N = Total number of outcomes.

The variable representing the selection of  Roberto and John is, <em>RJ</em>.

The favorable number of outcomes to select Roberto and John is, 1.

The total number of outcomes to select 2 employees is 10.

Compute the probability that Roberto and John attend the​ conference as follows:

P(RJ)=\frac{n(RJ)}{N}=\frac{1}{10}=0.10

Thus, the probability that Roberto and John attend the​ conference is 0.10.

(c)

The favorable outcomes of the event where Clarice attends the conference are:

n (C) = {MC, RC, JC and DC} = 4

Compute the probability that Clarice attends the​ conference as follows:

P(C)=\frac{n(C)}{N}=\frac{4}{10}=0.40

Thus, the probability that Clarice attends the​ conference is 0.40.

(d)

The favorable outcomes of the event where John does not attends the conference are:

n (J') = MR, MD, MC, RD, RC, DC

Compute the probability that John stays​ home as follows:

P(J')=\frac{n(J')}{N}=\frac{6}{10}=0.60

Thus, the probability that John stays​ home is 0.60.

4 0
3 years ago
I need help!! What is he answer??
IgorC [24]
2 is the answer i think
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