What is the length of the tabletop

Two equations are given below:

stealth61 [152]

a is given to us so just plug a into the first equation:

b-3 - 3b =9

Add 3 to both sides:

b-3b=12

Combine like terms:

-2b=12

Divide by -2 to get b by itself:

b=-6

The only answer with b as -6 is the first one, (-9,-6)

8 0

3 years ago

Read 2 more answers

Which table represents y as a function of x

hammer [34]

B the one u already have clicked

8 0

2 years ago

5. Landon bought a new car for $16,000 and it depreciates 4.5% every year. Write a function that describes

snow_tiger [21]

Answer:

<h3>The value C(t) of the car after 5 years is $12709.</h3>

Step-by-step explanation:

Given that Landon bought a new car for $16,000 and it depreciates 4.5% every year.

<h3>To find the value C(t) of the car after 5 years:</h3>

Initial value $C(0)= $16,000$

Depreciation rate is $r=\frac{4.5}{100}$

Period , t=5 years

$C(t)=C(0)(1-r)^t$

Substitute the values we get

$C(5)=16000(1-0.045)^5$

$=16000(0.955)^5$

$=16000(0.7943)$

∴ $C(5)=12708.8$

<h3>The value C(t) of the car after 5 years is $ 12709</h3>

3 0

2 years ago

work for a publishing company. The company wants to send two employees to a statistics conference. To be fair, the company deci

Yuki888 [10]

Answer:

(a) S = {MR, MJ, MD, MC, RJ, RD, RC, JD, JC, DC}

(b) The probability that Roberto and John attend the conference is 0.10.

(c) The probability that Clarice attends the conference is 0.40.

(d) The probability that John stays home is 0.60.

Step-by-step explanation:

It is provided that :

Marco (<em>M</em>), Roberto (<em>R</em>), John (<em>J</em>), Dominique (<em>D</em>) and Clarice (<em>C</em>) works for the company.

The company selects two employees randomly to attend a statistics conference.

(a)

There are 5 employees from which the company has to select two employees to send to the conference.

So the total number of ways to select two employees is:

${5\choose 2}=\frac{5!}{2!(5-2)!}=\frac{5\times 4\times 3!}{2\times 3!}=10$

The 10 possible samples are:

MR, MJ, MD, MC, RJ, RD, RC, JD, JC, DC

(b)

The probability of the event <em>E</em> is:

$P(E)=\frac{n(E)}{N}$

Here,

n (E) = favorable outcomes

N = Total number of outcomes.

The variable representing the selection of Roberto and John is, <em>RJ</em>.

The favorable number of outcomes to select Roberto and John is, 1.

The total number of outcomes to select 2 employees is 10.

Compute the probability that Roberto and John attend the conference as follows:

$P(RJ)=\frac{n(RJ)}{N}=\frac{1}{10}=0.10$

Thus, the probability that Roberto and John attend the conference is 0.10.

(c)

The favorable outcomes of the event where Clarice attends the conference are:

n (C) = {MC, RC, JC and DC} = 4

Compute the probability that Clarice attends the conference as follows:

$P(C)=\frac{n(C)}{N}=\frac{4}{10}=0.40$

Thus, the probability that Clarice attends the conference is 0.40.

(d)

The favorable outcomes of the event where John does not attends the conference are:

n (J') = MR, MD, MC, RD, RC, DC

Compute the probability that John stays home as follows:

$P(J')=\frac{n(J')}{N}=\frac{6}{10}=0.60$

Thus, the probability that John stays home is 0.60.

4 0

3 years ago

I need help!! What is he answer??

IgorC [24]

2 is the answer i think

7 0

3 years ago