Question

Dave and Sandy Hartranft are frequent flyers with a particular airline. They often fly from City A to City​ B, a distance of 828 miles. On one particular​ trip, they fly into the​ wind, and the flight takes 2 hours. The return​ trip, with the wind behind​ them, only takes 1 and
1/2 hours. If the wind speed is the same on each​ trip, find the speed of the wind and find the speed of the plane in still air.

Answer 1

Step-by-step explanation:

Let the speed of the plane in still air = x

and speed of wind = y

Now from city A to B

dIstance = speed  × time

732732 = (x - y) × 2 (1)

From city B to A

Distance = speed × time

732732 = (x + y) × 1.5 (2)

From (1) and (2)

2x - 2y = 1.5x + 1.5y

0.5x = 3.5y

x = 7y

If we plug in (1)

732732 = (7y - y) × 2

732732/12 = 12y/12

y = 61061

Since x = 7y

= 427427 miles/hr

Speed of still air plane is 427427 miles/hr

Speed of wind = 61061miles/hr

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