All categories

3 years ago

Find the average of$ 1148.37,$1760.44,$1143.57,and 1336.17 then round to the nearest cent

1 answer:

3 0

If you total them it equals $5388.55. and then divide by 4 and the average is 1347.1375 and the you round to nearest cent. $1347.14

You might be interested in

When studying the simultaneous responses to two categorical questions, we should set up a?

Dmitrij [34]

When studying the simultaneous responses to two categorical questions, we should develop a contingency table.

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

7 0

3 years ago

A bacteria population starts at 500 and doubles every 8 hours. What is the bacteria population after 12 hours?

Finger [1]

Answer:

1000

Step-by-step explanation:

After 8 hours, it becomes 1000, and because it doesn’t make it to 16 hours it stays at 1000.

4 0

3 years ago

Find the least common multiple of 4 and 10

Irina18 [472]

Answer:

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

An aircraft manufacturer wants to determine the best selling price for a new airplane. The company estimates that the initial co

Blizzard [7]

Answer:

$(a)$ $C(x)=500+20x-5x^{\frac{3}{4}}+0.01x^2$

$p(x)=320-7.7p$

$R(x)=(320-7.7p)p=320p-7.7p^2$

$(b)$ $x=82 \text{planes}$

$(c)$ $p=\$30.91 M\;\; \text{per plane}$

$(d)$ maximum profit $=\$ 15.90M$

Step-by-step explanation:

Given that,

The company estimates that the initial cost of designing the aeroplane and setting up the factories in which to build it will be 500 million dollars.

The additional cost of manufacturing each plane can be modelled by the function.

$m(x)=20x-5x^{\frac{3}{4}}+0.01x^2$

$(a)$ Find the cost, demand (or price), and revenue functions.

$C(x)=500+20x-5x^{\frac{3}{4}}+0.01x^2$

$p(x)=320-7.7p$

$R(x)=(320-7.7p)p=320p-7.7p^2$

$(b)$ Find the production level that maximizes profit.

$f=R(x)-C(x)$

$\Rightarrow f=320p-7.7p^2-(500+20x-5x^{\frac{3}{4}}+0.01x^2)$

$\Rightarrow df=320dp-15.4pdp-20dx+5(\frac{3}{4} )x^{\frac{-1}{4} }dx-0.02xdx$

$x=320-7.7p$

$p=\frac{320-x}{7.7}$

$\frac{dp}{dx} = \frac{-1}{7.7}$

$\frac{df}{dx}=\frac{320}{-7.7} -\frac{15.4(320-x) }{7.7(\frac{-1}{7.7} )}-20+5\frac{3}{4} x^{\frac{-1}{4}} -0.02x=0$

$\Rightarrow -41.5584+83.1169-0.2597x-20+3.75x^{\frac{-1}{4} }-0.02x=0$

$\Rightarrow 21.5585+3.75x^{\frac{-1}{4} }-0.279x=0$

$\Rightarrow x=82 \text{planes}$

$(c)$ Find the associated selling price of the aircraft that maximizes profit.

$p=\frac{320-82}{7.7}$

$\Rightarrow p=\$30.91 M\;\; \text{per plane}$

$(d)$ Find the maximum profit.

Manufacturing cost of one plane is:

$m(1)=20-5+0.01$

$=\$15.01 M$

maximum profit $=\$(30.91-15.01)M$

$=\$15.90M$

3 0

3 years ago

For what value of x must ABCD be a parallelogram?

bija089 [108]

5x = 6x-7

subtract 6x from each side

-x=-7

x=7

8 0

3 years ago

Read 2 more answers