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3 years ago

Find the average of$ 1148.37,$1760.44,$1143.57,and 1336.17 then round to the nearest cent

1 answer:

3 0

If you total them it equals $5388.55. and then divide by 4 and the average is 1347.1375 and the you round to nearest cent. $1347.14

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Find the 15th term of the geometric sequence 2 , -8 , 32

marishachu [46]

Answer:

first term (a)= 2

second term (b) = -8

common ratio (r) = -8/2 = -4

15th term = ar^ (n-1)

= 2* (-4)^ 14 =536870912

Step-by-step explanation:

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2 years ago

Find the mean? Read question rest is done.

Ulleksa [173]

Answer:

I believe its 8

Step-by-step explanation:

9 + 10 + 13 + 2 +6 = 40 / 5 = 8

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3 years ago

I neee #14 PLEASE! Thanks! <3

Ksenya-84 [330]

I hope this helps you

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2 years ago

Which ordered pair represents the solution to the system of equations? {4x−2y=18−3x−4y=−8 (4, −1) (5, 1) (−1, 4) (43, 1)

Ilia_Sergeevich [38]

Answer:

A g imma need the answer too

Step-by-step explanation:

6 0

2 years ago

Find the particular solution of the differential equation that satisfies the initial condition(s). f ''(x) = x−3/2, f '(4) = 1,

sweet [91]

Answer:

Hence, the particular solution of the differential equation is $y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x$ .

Step-by-step explanation:

This differential equation has separable variable and can be solved by integration. First derivative is now obtained:

$f'' = x - \frac{3}{2}$

$f' = \int {\left(x-\frac{3}{2}\right) } \, dx$

$f' = \int {x} \, dx -\frac{3}{2}\int \, dx$

$f' = \frac{1}{2}\cdot x^{2} - \frac{3}{2}\cdot x + C$ , where C is the integration constant.

The integration constant can be found by using the initial condition for the first derivative ( $f'(4) = 1$ ):

$1 = \frac{1}{2}\cdot 4^{2} - \frac{3}{2}\cdot (4) + C$

$C = 1 - \frac{1}{2}\cdot 4^{2} + \frac{3}{2}\cdot (4)$

$C = -1$

The first derivative is $y' = \frac{1}{2}\cdot x^{2}- \frac{3}{2}\cdot x - 1$ , and the particular solution is found by integrating one more time and using the initial condition ( $f(0) = 0$ ):

$y = \int {\left(\frac{1}{2}\cdot x^{2}-\frac{3}{2}\cdot x -1 \right)} \, dx$

$y = \frac{1}{2}\int {x^{2}} \, dx - \frac{3}{2}\int {x} \, dx - \int \, dx$

$y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x + C$

$C = 0 - \frac{1}{6}\cdot 0^{3} + \frac{3}{4}\cdot 0^{2} + 0$

$C = 0$

Hence, the particular solution of the differential equation is $y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x$ .

5 0

3 years ago