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butalik [34]
3 years ago
11

1. Which of the following belongs in the first column of a formal proof?

Mathematics
2 answers:
navik [9.2K]3 years ago
8 0

Answer:

i believe the answer would be c)theorems

Step-by-step explanation:

sorry if im wrong

olasank [31]3 years ago
4 0

Answer:

b. statements

Step-by-step explanation:

Took the quiz and got it right.

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1<br> Select all relations that are functions from the choices below
Daniel [21]

Answer:

Option (D).

Step-by-step explanation:

If the graph of a relation has two output values for a single input value, relation will not be considered to be a function.

Option (A).

For the input values of x = -1, there are two output values, y = -1, 1.

Therefore, given relation is not a function.

Option (B).

Since, all the parabolas don't represent a function, given parabola in the graph is not a function.

Option (C).

Not a function. It's a relation.

Option (D).

Line plotted in the graph has a distinct output value for every input value.

Therefore, the given graph represents a linear function.

7 0
4 years ago
Find the centrroid of the triangle with the given vertices F(1, 5), G(-2, 7) and H(-6, 3)
jekas [21]

\qquad \textit{Centroid of a Triangle} \\\\ \left(\cfrac{x_1+x_2+x_3}{3}~~,\cfrac{y_1+y_2+y_3}{3}~~ \right)\quad \begin{cases} F(\stackrel{x_1}{1},\stackrel{y_1}{5})\\\\ G(\stackrel{x_2}{-2},\stackrel{y_2}{7})\\\\ H(\stackrel{x_3}{-6},\stackrel{y_3}{3}) \end{cases} \\\\\\ \left( \cfrac{1-2-6}{3}~~,~~\cfrac{5+7+3}{3} \right)\implies \left( \cfrac{-7}{3}~~,~~\cfrac{15}{3} \right)\implies \left( -2\frac{1}{3}~~,~~5 \right)

4 0
3 years ago
hey everyone hope everyone are fine .... plz follow me thank me and Mark me as brainliest... I'll favor you guys​
Vedmedyk [2.9K]

Answer:

aww thanks for your concern hope we'll help each other in the future

thanking you,

(ㆁωㆁ)

4 0
3 years ago
Expand the given power using the Binomial Theorem. (10k – m)5
agasfer [191]

Answer:

(10k - m)^{5}=100000k-50000k^{4}m+10000k^{3}m^{2}-1000k^{2}m^{3}+50km^{4}-m^{5}

Step-by-step explanation:

* Lets explain how to solve the problem

- The rule of expand the binomial is:

(a+b)^{n}=(a)^{n}+nC1(a)^{n-1}(b)+nC2(a)^{n-2}(b)^{2}+nC3(a)^{n-3}(b)^{3}+...............+(b)^{5}

∵ The binomial is (10k-m)^{5}

∴ a = 10k , b = -m and n = 5

∴ (10k-m)^{5}=(10k)^{5}+5C1(10k)^{4}(-m)+5C2(10k)^{3}(-m)^{2}+5C3(10k)^{2}(-m)^{3}+5C4(10k)^{1} (-m)^{4}+5C5(10k)^{0}(-m)^{5}

∵ 5C1 = 5

∵ 5C2 = 10

∵ 5C3 = 10

∵ 5C4 = 5

∵ 5C5 = 1

∴ (10k-m)^{5}=100000k^{5}+(5)(10000)k^{4}(-m)+(10)(1000)k^{3}(m^{2})+(10)(100)k^{2}(-m^{3})+5(10k)^{1} (m^{4})+(10k)^{0}(-m^{5})

∴ (10k-m)^{5}=100000k^{5}-50000)k^{4}m+10000k^{3}m^{2}-1000k^{2}m^{3}+50km^{4}-m^{5}

5 0
3 years ago
Garden one has 9 more bushes of red currant than garden two. If 3 bushes were transplanted from garden two to garden one, then g
Vesnalui [34]

Garden one and two are both unknown, so I am choosing to call garden 2 X and then label garden 1 with comparisons to X.

It is tempting to list:

Garden Two = X

Garden One = X + 9

BUT there is an easier way. We are told that when 3 bushes are taken from garden 2 (x-3) and put in garden 1 (x + 12) then garden one has 1.5 times more than garden two.

Set it up like this:

1.5 ( x - 3) = x + 12 (because 1.5 times garden 2 will give us garden 1)

1.5x - 4.5 = x + 12 (Distribute)

.5x = 16.5 (Use subtraction to move variables to the right and other numb left)

x = 33 for Garden 2

33  + 9 for Garden 1 = 42


7 0
3 years ago
Read 2 more answers
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