Who has the ps5 i do

Find the value of x in each case:

Margaret [11]

Answer:

x = 11°

4x = 44°

Step-by-step explanation:

Line BC || Line EF... (given)

BF is transversal.

$\angle BFG + \angle BFE = 180\degree\\.. (straight \: line \: \angle 's) \\ + \angle BFE = 180\degree\\\angle BFE = 180\degree-147\degree \\\angle BFE = 33\degree\\$

$\angle BED$ is exterior angle of $\angle EBF$

Hence, by remote interior angle theorem of triangle, we have:

$m\angle BED = m\angle EBF + \angle BFE \\4x = x + 33\degree \\4x - x = 33\degree \\3x = 33\degree \\x = \frac{33}{3}\\\huge \purple {\boxed {x = 11\degree}} \\4x = 4\times 11\degree \\\huge \orange{\boxed {4x = 44\degree}}$

6 0

3 years ago

The diameter of a circle measures 12 m. What is the circumference of the circle?

andrezito [222]

Answer:

37.7

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

A company determines that its marginal revenue per day is given by R' ( t ) , where R ( t ) is the total accumulated revenue, in

DedPeter [7]

Answer:

Step-by-step explanation:

Total profit function is equal to Total revenue function minus Total Cost function.

To get both Revenue function and Cost function, integrate the Marginal functions as follows:

R(t) = 108.7312t^2

Where 80et = 217.4624t

(e =2.71828)

C(t) = 80t - 0.4t^2

P(t) = R(t) - C(t) = 109.1312t^2 - 80t

When t=0, P=0

When t=1, P=29.1312

When t=2, P=276.5248

When t=3, P=742.1808

And so on ...

Summing the daily profits, total profit for the 10 days is 37,615.512 dollars which equals 3,761551.2 cents

(B)

Average daily profit for the first 10 days (in dollars) is 37,615.512÷10 = 3,761.5512 dollars

= 376,155.12 cents

3 0

3 years ago

Oliver interviewed 30% of the 9th grade class and 70% of the 10th grade class at his school. Jenny interviewed 75% of the 9th gr

mixer [17]

Answer:

A . 36

Step-by-step explanation:

We are given a total of 176 interviewed by Oliver and a total of 140 interviewed by Jenny. To find how many more 10th graders than 9th graders were interviewed, subtract the totals given

176 - 140 = 36

This is how we came to the answer:

We are given 70% of the 10th-grade and 30% of the 9th-grade with a total of 176 for Oliver.

While we're given 75% of the 9th-grade class and 25% of the 10th-grade with a total of 140 interviewed by Jenny

<u>Oliver's Interviewees</u>

10-graders

Firstly, let's find what the number of 9th-graders was interviewed by Oliver; find the percentage of the 9th-graders by the total;

70% of 176 =

$\frac{70}{100} * \frac{176}{1}$

Cross multiply

123.2 were 10-graders interviewed by Oliver

9th-graders

Now, to find the number of 9th-graders was interviewed by Oliver; find the percentage of the 9th-graders by the total;

30% of 176 =

$\frac{30}{100} * \frac{176}{1}$

Cross multiply

52.8 were 9th-graders interviewed by Oliver

<u>Jenny's Interviewees</u>

9th-graders

Firstly, let's find what the number of 9th-graders was interviewed by Jenney; find the percentage of the 9th-graders by the total;

75% of 140 =

$\frac{75}{100} * \frac{140}{1}$

Cross multiply

105 students were 9th-graders interviewed by Jenney.

10th-graders

Now, to find the number of 10th-graders was interviewed by Jenney; find the percentage of the 10th-graders by the total;

25% of 140 =

$\frac{25}{100} * \frac{140}{1}$

Cross multiply

35 students were 10th-graders interviewed by Jenney.

<u />

<u>Total calculation</u>

Use the results and sum them up by 9th-grade plus 9th-grade and 10th-grade plus 10-grade. Then subtract the amount gotten from 9th-grade away from the amount gotten from 10th-grade;

Oliver's 9th-grade = 52.8

Jenny's 9th-grade = 105

105 + 52.8 = 157.8

Oliver's 10th-grade = 123.2

Jenny's 10th-grade = 35

123.2 + 35 = 158.2

Total calculation: 158. 2 - 157.8 = 0.4

<h2>Therefore, there are 36 more 10th than 9th.</h2>

<u />

<h3><u>Extra Info:</u></h3>

<u>Oliver's Interviewees Percentage</u>

Since we are given 30% of the 9th-grade class and 70% of the 10th-grade class, first, let's add the percentages. To do so, set it up as a fraction;

30% = $\frac{30}{100}$ while, 70% = $\frac{70}{100}$

Now solve it;

$\frac{30}{100} + \frac{70}{100}$

Simplify; cancel bottom zero's;

$\frac{30}{1} + \frac{70}{1}$

Add the remaining numerators;

30 + 70 = 100

Which is 100%

<u>Jenny's Interviewees Percentage</u>

Since we're given 75% of the 9th-grade class and 25% of the 10th-grade, it will end up the same answer. I'll show you how; first, let's add the percentages. To do so, set it up as a fraction;

25% = $\frac{25}{100}$ and, 75% = $\frac{75}{100}$