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Leokris [45]
3 years ago
9

What is the measurement of

Mathematics
1 answer:
vampirchik [111]3 years ago
5 0
<h2><em>Answer:</em></h2><h3><em>1</em><em>0</em><em>5</em><em>°</em></h3>

<em>Solution</em><em>,</em>

<em>X+</em><em>7</em><em>5</em><em>=</em><em>1</em><em>8</em><em>0</em><em>°</em><em>(</em><em> </em><em>sum </em><em>of </em><em>angle </em><em>in </em><em>straight</em><em> </em><em>line</em><em>)</em>

<em>or,</em><em>X=</em><em>1</em><em>8</em><em>0</em><em>°</em><em>-</em><em>7</em><em>5</em><em>°</em>

<em>X</em><em>=</em><em>1</em><em>0</em><em>5</em><em>°</em>

<em>Hope </em><em>it</em><em> </em><em>will</em>

<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em>

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Answer:

The diameter decreases at the rate of 0.0796 cm/min when the diameter is 10 cm.

Step-by-step explanation:

A snowball is spherical, so it's area is given by the following formula:

A = 4\pi r^{2}

The radius is half the diameter so:

A = 4\pi (\frac{d}{2})^{2}

A = 4\pi \frac{d^{2}}{4}

A = \pi d^{2}

If a snowball melts so that its surface area decreases at a rate of 5 cm2/min, find the rate at which the diameter decreases when the diameter is 10 cm.

We have to find \frac{dd}{dt} when \frac{dA}{dt} = -5, d = 10

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Applying implicit differentiation:

We have to variables(A and d), so:

\frac{dA}{dt} = 2\pi d \frac{dd}{dt}

-5 = 2\pi (10) \frac{dd}{dt}

\frac{dd}{dt} = -\frac{5}{20\pi}

\frac{dd}{dt} = -0.0796

The diameter decreases at the rate of 0.0796 cm/min when the diameter is 10 cm.

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