Question

An electronics company manufactures widescreen television sets in several different sizes. the rectangular viewing area of each television size is similar to the viewing areas of the other sizes. the company's 42-inch widescreen television has a viewing area perimeter of approximately 144.4 inches. what is the viewing area perimeter of the company's 46-inch widescreen television?

Answer 1

Knowing that the tow rectangular viewing area peremiters are similar, we can establish a rule of three to find the viewing area of the 46-inch widescreen.

$\frac{42}{144.4} = \frac{46}{x}$
Now we solve for x to find the viewing area of the 46-inch widescreen:
$x= \frac{(46)(144.4)}{42}$
$x=158.6$

We can conclude that the viewing area perimeter of the 46-inch widescreen television set is approximately 158.6 inches.