Ask question

Ask question

All categories

mr Goodwill [35]

3 years ago

14

In a single organism, what do you notice about the relative proportions of dna bases?

2 answers:

andrew-mc [135]3 years ago

8 0

Answer:

In an organism, amount of adenine base is equal to amount of thymine base. And amount of guanine base is equal to amount of cytosine base.

Explanation:

The relative proportions of DNA bases in all the organisms with double stranded DNA as genome follow Chargaff's rule. Accordingly, total number of purine bases (adenine + guanine) in DNA is always equals to total number of pyrimidine bases (cytosine + thymine). Since adenine pairs with thymine and guanine pairs with cytosine, number to adenine base is equal to that of thymine and total amount of guanine base is equal to that of cytosine base.

kakasveta [241]3 years ago

7 0

The awnser are A and D

You might be interested in

Chapter 7 cell structure and function

MariettaO [177]

What are you asking I would love to help

4 0

3 years ago

Alex poured some pond water into three beakers. She then put waterweed into each beaker. She put the beakers in different places

Alenkasestr [34]

Answer:

The box has blocked the sunlight from the waterweed and it has stopped photosynthesising

Explanation:

5 0

2 years ago

The 14th and 15th Amendments protected African Americans' right to citizenship and the right to vote.

Reil [10]

Answer:

The answer is they passed the Jim Crow Laws, D

8 0

3 years ago

Suppose the human trait for hair type is controlled by a simple dominant and recessive relationship at one locus. Curly hair, C,

myrzilka [38]

Answer:

A) The frequency of the dominant allele, C $= 0.4376$

B) frequency of the heterozygous genotype, Cc $= 0.2461$

Explanation:

Given -

Curly hair, C, is the dominant allele, and straight hair, c, is the recessive allele

Number of students with curly hair is $37$

Thus frequency of genotype "CC"

$= q^{2} = \frac{37}{117} \\= 0.3162$

Thus, frequency of allele "q"

$= \sqrt{0.3162} \\= 0.5623$

As per Hardy Weinberg's first equation-

$p+q=1$

Substituting the value of q, we get -

$p+0.5623=1\\p= 0.4376$

As per Hardy Weinberg's second equation -

$p^2+q^2+2pq=1\\$

Substituting the values of "p" and "q" we get -

$0.4376^{2} + 0.3162+2pq = 1\\2pq = 0.2461\\$

Hence,

A) The frequency of the dominant allele, C $= 0.4376$

B) frequency of the heterozygous genotype, Cc $= 0.2461$

8 0

3 years ago

Read 2 more answers

The renal arteries supply blood to the kidneys.<br><br><br> TrueFalse

zvonat [6]

Yes, this is true...

4 0

3 years ago

Read 2 more answers