What is the interquartile range of the data set below? Growth in feet of oak trees: 68,80,73,90,120,94,76,112,101,94,72 (1) 22
sdas [7]
<span>68,80,73,90,120,94,76,112,101,94,72 --->
68, 72, 73, 76, 80, 90, 94, 94, 101, 112, 120
Median = 90
Lower Median = 73
Upper Median = 101
IQR = 101 - 73
IQR = 28</span>
= -10x^2 - 6xy + 6xz
hope it helps
Answer:
213.3
Step-by-step explanation:
The volume of a pyramid is 1/3 base times height.
Using this formula, our square base is 8*8, or 64 square units.
Multiplying that by the height, 10. We get 64*10, 640.
Finally dividing by 3, we have 213.3333333333...
Rounding that to the nearest tenth, 213.3.
Do you want to solve for x and y?
What is the objective?
Answer:
height of second rectangular prism is 5 meters
Step-by-step explanation:
