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2 years ago

Yo does anyone know how to do this?

Mathematics

1 answer:

Sonbull [250]2 years ago

3 0

Answer:

The horizontal line is the x-axis and the vertical line is the y-axis.

Step-by-step explanation:

The horizontal line is the x-axis and the vertical line is the y-axis. It's a fact. You can graph the lines by inserting the equations using the graphing calculator, which is the tab next to the one you have right now ;)

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Please I need ASAP. First one to answer will get Brainyist.

Rzqust [24]

Answer:

I'm just here for my points sorry bro

4 0

3 years ago

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Find the coordinates of the other endpoint of the segment, given its midpoint and one endpoint. (Hint: Let (x,y) be the unkno

makkiz [27]

Step-by-step explanation:

Hey, there!!

Here, one point is A(10,8) and P(8,5) is the midpoint.

Let B(x,y) be the another end point.

Now,

Using midpoint formulae,

$p(x.y) = \frac{x1 + x2}{2} . \frac{y1 + y2}{2}$

$p(8.5) = ( \frac{10 + x}{2} . \frac{8 + y}{2} )$

Since they are equal,equating with their corresponding elements we get,

$8 = \frac{10 + x}{2}$

or, 16 = 10 + x

or, x=16-10

Therefore, x = 6

Now,

$5 = \frac{8 + y}{2}$

or, 10 = 8 + y

or, y = 2

Therefore, The coordinates of another point are B(6,2)

Hope it helps .....

8 0

3 years ago

I will give brainliest if this is answerd in 10 min it is timed here it is:this is worth 100 pts

Jobisdone [24]

Answer:

customary system:

miles

ounces

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deciliters

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Step-by-step explanation:

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3 years ago

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Find the maximum value of the function f(x) = -1.9x^2 + 24x – 71.3 to the nearest hundredth.

d1i1m1o1n [39]

Being that the system is quadratic—with parabola opening downwards—you’re going to need to find the vertex. You can find the x coordinate of the vertex with -b/2a . Then plug in for x to find the y coordinate…

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2 years ago

Assume that the total revenue received from the sale of x items is given by, R(x)equals34 ln (4 x plus 5 ), while the total c

katen-ka-za [31]

Answer:

63 units

Step-by-step explanation:

The profit function P(x) is given by the revenue function minus the cost function:

$P(x) = R(x) - C(x)\\P(x) = 34ln(x+5)-\frac{x}{2}$

The number of units sold 'x' for which the derivate of the profit function is zero, is the number of units that maximizes profit:

$P(x) = 34ln(x+5)-\frac{x}{2}\\P'(x) =0= \frac{34}{x+5}-\frac{1}{2}\\x+5=68\\x=63\ units$

The number of units that should be manufactured so that profit is maximum is 63 units.

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3 years ago