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3 years ago

8

Un conejo vio seis elefantes mientras se dirigía al río. Cada elefante vio dos monos que se dirigían hacia el río. Cada mono sos

tiene un loro en sus manos. ¿Cuántos animales van al río?

1 answer:

Ganezh [65]3 years ago

3 0

Answer:

Serían cinco animales

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Graph f(x)=-2|x+4| khan academy

Vladimir [108]

Answer:

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

22=2(w+7)-4w<br> What is w?

SOVA2 [1]

Solve for w by simplifying both sides of the equation, then isolating the variable.

w=−4

Let's solve your equation step-by-step.

22=2(w+7)−4w

Step 1: Simplify both sides of the equation.

22=2(w+7)−4w

22=(2)(w)+(2)(7)+−4w (Distribute)

22=2w+14+−4w

22=(2w+−4w)+(14) (Combine Like Terms)

22=−2w+14

22=−2w+14

Step 2: Flip the equation.

−2w+14=22

Step 3: Subtract 14 from both sides.

−2w+14−14=22−14

−2w=8

Step 4: Divide both sides by -2.

−2w /−2 = 8 /−2

Answer:

w=−4

5 0

3 years ago

Read 2 more answers

1. Which monomial has the same degree as 6a2b8c? A 18t8 B 12p6q5 C 9a5b3c2 D 6w4x2y3z3

Olegator [25]

Answer: "B. $12p^6q^5$

Step-by-step explanation:

The given monomial : $6a^2b^8c$

Degree of this monomial = Sum of powers of variables=2+8+1= 11

Let's check all the options

A $18t^8$

Degree = 8

B $12p^6q^5$

Degree = 6+5 =11

C $9a^5b^3c^2$

Degree = 5+3+2=10

D $6w^4x^2y^3z^3$

Degree =4+2+3+3=12

We can see that only option B has degree 11.

So, the monomial has the same degree as $6a^2b^8c$ is "B. $12p^6q^5$ "

8 0

3 years ago

Help me please on this math question

rjkz [21]

Answer:

729 * 10^-45

Step-by-step explanation:

Here, we want to expand the value based on the exponent

We have the power multiplying every term in the bracket

That would be;

9^3•10^-45

= 729 * 10^-45

5 0

3 years ago

A chain 27 feet long whose weight is 95 pounds is hanging over the edge of a tall building and does not touch the ground. How mu

bazaltina [42]

Answer:

Work done $= 2,565$ lb-ft

Step-by-step explanation:

The density of the chain in lb/ft is equal to

$\frac{95}{27}$ lb/ft

Total Work done is equal to the summation of work done up to the top of building.

We will use integration for this evaluation.

The mathematical relation is as follows

$\int\limits^{40}_0 {X} \, pdx$

where "p" is the density

Substituting the given values, we get

$\frac{95}{27} \int\limits^{27}_0 {X} \, dx\\\frac{95}{27} X^2\int\limits^{27}_0\\ \frac{95}{27} {27^2 - 0^2}\\\frac{95}{27} * 27 * 27\\95* 27\\= 2,565$

Work done $= 2,565$ lb-ft

6 0

3 years ago