Answer
z11.7 is between 1 and 2 standard deviations of the mean.
Step-by-step explanation:
The equation of the elipse is given by:

The equation of an elipse of center
is given by:

Values a and b are found according to the <u>vertices and the eccentricity</u>.
It has vertices at (1,0) and (27,0), thus:




It has eccentricity of
, thus:



Thus, b is given according to the following equation:





The equation of the elipse is:

A similar problem is given at brainly.com/question/21405803
I believe it's cones, cylinders, and spheres, hope this really help, and good luck
The sum of prime factors of 2014 is 74
<h3><u>Solution:</u></h3>
Given that to find sum of prime factors of 2014
Let us first find the prime factors of 2014
A prime number is a whole number greater than 1 whose only factors are 1 and itself
"Prime Factorization" is finding which prime numbers multiply together to make the original number.
<em><u>Prime factors of 2014:</u></em>
The Prime Factorization is:

Thus the prime factors of 2014 are 2, 19, 53
<em><u>Let us now find the sum of prime factors of 2014</u></em>
sum of prime factors of 2014 = 2 + 19 + 53 = 74
Thus the sum of prime factors of 2014 is 74
You have two totals: total # of bills and total amount of $. Using x as #of 20s, and y as # of 50s, you can use the system
x+y=18
20x+50y=450