Ask question

Ask question

All categories

3 years ago

13

Every week (w) Sandra will save $10. Which algebraic expression could Sandra use to calculate how much money she has saved after

any number of weeks

1 answer:

stiv31 [10]3 years ago

4 0

Y=10t
where
y - her total total savings
t - number of weeks

You might be interested in

Question 2 of 5

Mice21 [21]

Answer:

30

Step-by-step explanation:

4 0

3 years ago

One package of socks cost $7. How many packages can you but with $56?

Akimi4 [234]

Step-by-step explanation:

$7 = 1 package socks

%56 = ??

$56/$7 × 1 package socks

= 8 × 1

= 8 package socks

Hope it helps!

4 0

3 years ago

For which angle theta is cos theta =-1?<br>a) 270<br>b) 360<br>c) 450<br>d) 540

yanalaym [24]

Answer:

540°.

Step-by-step explanation:

On a unit circle, cos θ = -1 at 180°.

However, cos θ has a period of 2π, or 360°. This means that cos θ will equal to -1 again after 2π.

To solve for the angle:

180° + 360° = 540°. This is the next angle at which cos θ = -1.

7 0

3 years ago

Read 2 more answers

Find an equation of the tangent line to the graph of

lakkis [162]

Answer:

y + 4 = -3 (x - 5)

In other words,

y = -3 x + 11

Step-by-step explanation:

The slope of the tangent line to y = g(x) at x = 5 is the same as the value of g'(x). g'(5) = 3. Therefore, 3 will be the slope of the tangent line.

The tangent line goes through the point of tangency (5, g(5)). g(5) = -4. Therefore, the tangent line passes through the point (5, -4).

Apply the slope-point form of the line. The equation for a line with slope <em>m</em> that goes through point (a, b) will be y - b = m(x - a). For the tangent line in this question,

m = 3,
a = 5, and
b = -4.

What will be the equation of this line?

6 0

3 years ago

Read 2 more answers

John, sally, Natalie would all like to save some money. John decides that it would be best to save money in a jar in his closet

stiv31 [10]

Answer:

Part 1) John’s situation is modeled by a linear equation (see the explanation)

Part 2) $y=100x+300$

Part 3) $\$12,300$

Part 4) $\$2,700$

Part 5) Is a exponential growth function

Part 6) $A=6,000(1.07)^{t}$

Part 7) $\$11,802.91$

Part 8) $\$6,869.40$

Part 9) Is a exponential growth function

Part 10) $A=5,000(e)^{0.10t}$ or $A=5,000(1.1052)^{t}$

Part 11) $\$13,591.41$

Part 12) $\$6,107.01$

Part 13) Natalie has the most money after 10 years

Part 14) Sally has the most money after 2 years

Step-by-step explanation:

Part 1) What type of equation models John’s situation?

Let

y ----> the total money saved in a jar

x ---> the time in months

The linear equation in slope intercept form

$y=mx+b$

The slope is equal to

$m=\$100\ per\ month$

The y-intercept or initial value is

$b=\$300$

so

$y=100x+300$

therefore

John’s situation is modeled by a linear equation

Part 2) Write the model equation for John’s situation

see part 1)

$y=100x+300$

Part 3) How much money will John have after 10 years?

Remember that

1 year is equal to 12 months

so

$10\ years=10(12)=120 months$

For x=120 months

substitute in the linear equation

$y=100(120)+300=\$12,300$

Part 4) How much money will John have after 2 years?

Remember that

1 year is equal to 12 months

so

$2\ years=2(12)=24\ months$

For x=24 months

substitute in the linear equation

$y=100(24)+300=\$2,700$

Part 5) What type of exponential model is Sally’s situation?

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$P=\$6,000\\ r=7\%=0.07\\n=1$

substitute in the formula above

$A=6,000(1+\frac{0.07}{1})^{1*t}\\ A=6,000(1.07)^{t}$

therefore

Is a exponential growth function

Part 6) Write the model equation for Sally’s situation

$A=6,000(1.07)^{t}$

see the Part 5)

Part 7) How much money will Sally have after 10 years?

For t=10 years

substitute the value of t in the exponential growth function

$A=6,000(1.07)^{10}=\$11,802.91$

Part 8) How much money will Sally have after 2 years?

For t=2 years

substitute the value of t in the exponential growth function

$A=6,000(1.07)^{2}=\$6,869.40$

Part 9) What type of exponential model is Natalie’s situation?

we know that

The formula to calculate continuously compounded interest is equal to

$A=P(e)^{rt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

e is the mathematical constant number

we have

$P=\$5,000\\r=10\%=0.10$

substitute in the formula above

$A=5,000(e)^{0.10t}$

Applying property of exponents

$A=5,000(1.1052)^{t}$

therefore

Is a exponential growth function

Part 10) Write the model equation for Natalie’s situation

$A=5,000(e)^{0.10t}$ or $A=5,000(1.1052)^{t}$

see Part 9)

Part 11) How much money will Natalie have after 10 years?

For t=10 years

substitute

$A=5,000(e)^{0.10*10}=\$13,591.41$

Part 12) How much money will Natalie have after 2 years?

For t=2 years

substitute

$A=5,000(e)^{0.10*2}=\$6,107.01$

Part 13) Who will have the most money after 10 years?

Compare the final investment after 10 years of John, Sally, and Natalie

Natalie has the most money after 10 years

Part 14) Who will have the most money after 2 years?

Compare the final investment after 2 years of John, Sally, and Natalie

Sally has the most money after 2 years

3 0

3 years ago

Read 2 more answers