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Alex Ar [27]
2 years ago
9

A classroom is 20 feet long. The office is 82% longer than the classroom. How long is the office?

Mathematics
1 answer:
enyata [817]2 years ago
4 0

Answer:

The length of the office is  36.4 ft

Step-by-step explanation:

The length of the classroom  =  20 ft long

The length of the office =  20 ft + 82% of the classroom length

Now, 82 % of classroom length  =  82 % of 20 ft

⇒ \frac{82}{100}   \times 20  =  16.4

or, 82% of 20 ft = 16.4 ft

⇒The length of the office  = 20 ft + 16.4 ft  = 36.4 ft

Hence, the length of the office =  36.4 ft

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Bill and Joe have 60 dollars between them. Bill has half as much as Joe. How much does Bill have?
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What is 294 miles every 14 gallons
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Suppose that 10% of all homeowners in an earthquake-prone area of California are insured against earthquake damage. Four homeown
guapka [62]

Remainder of question:

Find the probability distribution of x

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The random variable x is defined as: X = {0, 1, 2, 3, 4}

The probability distribution of X:

P(X = 0) = 0.656

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P(X= 2) = 0.0486

P(X=3) = 0.0036

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Step-by-step explanation:

Sample size, n = 4

Random variable, X = {0, 1, 2, 3, 4}

10% (0.1) of the homeowners are insured against earthquake, p = 0.1

Proportion of homeowners who are not insured against earthquake, q = 1 - 0.1

q = 0.9

Probability distribution of x,

P(X = r) = ^nC_r *p^r q^{n-r} \\\\P(X= 0) =(^4C_0 *p^1 q^4 )\\P(X=0) = (^4C_0 *0.1^0 0.9^4 ) = 0.656\\P(X= 1)= (^4C_1 *p^1 q^3 )\\P(X=1) = (^4C_1 *0.1^1 0.9^3 ) = 0.2916\\P(X= 2)=( ^4C_2 *p^2 q^2) \\P(X=2) = (^4C_2 *0.1^2 0.9^2 ) = 0.0486\\P(X= 3) = (^4C_3 *p^3 q^3) \\ P(X=3) = (^4C_3 *0.1^3 0.9^1 ) = 0.0036\\P(X= 4) =  (^4C_4 *p^4 q^0 )\\ P(X=4) =(^4C_4 *0.1^4 0.9^0 ) = 0.0001

5 0
3 years ago
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