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3 years ago

Find the value of x in the triangle shown below

Mathematics

1 answer:

olga nikolaevna [1]3 years ago

8 0

Answer:

102

Step-by-step explanation:

it is an isosceles triangle as two sides are equal i.e 3.3 so angles opposite to equal sides are also equal so 39 plus 39 plus x = 180°

78 plus x =180

x=180-78

x=102°

hope it helps

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what is the equation to seven less than the product of twice a number is greater than 5 more than the same number

postnew [5]

<span>seven less than (-7) than the product of twice a number (2x) is greater than (>) five more than (+5) the same number (x)

2x-7>x+5
treat the > sign as an equals for now
2x-7=x+5
subtract x from both sides
x-7=5
add 7 to both sides
x=12
put the > sign back in
x>12</span>

7 0

3 years ago

Read 2 more answers

I did something wrong could you help?

posledela

Answer:

Slope = 1/2

y-intercept = 30

Equation : y = 1/2x + 30

D. 150 miles

Step-by-step explanation:

We can use the two visible points you marked on the graph.

They are (0,30) which is also the y-intercept and (20,40).

Calculate change of y over change of x.

10/20 or 1/2

So the slope is 1/2 and the y-intercept is 30.

Therefore, using y = mx + b form, the equation is y = 1/2x + 30

Then, to find how many miles you drove if the cost was $105, we can plug in 105 for y in the equation.

105 = 1/2x + 30

75 = 1/2x

x = 150

8 0

3 years ago

Translate this sentence into an equation

tiny-mole [99]

Answer:

59 = 16 + d

Step-by-step explanation:

7 0

3 years ago

Given cosα = −3/5, 180 < α < 270, and sinβ = 12/13, 90 < β < 180

torisob [31]

I got

$- \frac{6 3}{65}$

What we know

cos a=-3/5.

sin b=12/13

Angle A interval are between 180 and 270 or third quadrant

Angle B quadrant is between 90 and 180 or second quadrant.

What we need to find

Cos(b)

Cos(a)

What we are going to apply

Sum and Difference Formulas

Basics Sine and Cosines Identies.

1. Let write out the cos(a-b) formula.

$\cos(a - b) = \cos(a) \cos(b) + \sin(a) \sin(b)$

2. Use the interval it gave us.

According to the given, Angle B must between in second quadrant.

Since sin is opposite/hypotenuse and we are given a sin b=12/13. We. are going to set up an equation using the pythagorean theorem.

${12}^{2} + {y}^{2} = {13}^{2}$

$144 + {y}^{2} = 169$

$25 = {y}^{2}$

$y = 5$

so our adjacent side is 5.

Cosine is adjacent/hypotenuse so our cos b=5/13.

Using the interval it gave us, Angle a must be in the third quadrant. Since cos is adjacent/hypotenuse and we are given cos a=-3/5. We are going to set up an equation using pythagorean theorem,

$( - 3) {}^{2} + {x}^{2} = {5}^{2}$