Answer:
The linear approximation of B(t) at t = 2.2 estimates B(t) = 9 for t = 2.8328
Step-by-step explanation:
b'(2.2) = 8 * e^(0.2cos(2.2)) = 7.1117 and b(2.2) = 4.5. The linear approximation of B(t) at t = 2.2 is
L(t) = 7.1117*(t-2.2) + 4.5
We want t so that L(t) = 9
9 = 7.1117*(t-2.2) + 4.5
4.5 = 7.1117 *(t-2.2)
t-2.2 = 4.5/7.1117 = 0.6327601
t = 2.2+0.6327601 = 2.8328
That as an expression would be
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