Answer:
f(x) = -3(x+3)(x-1)
Step-by-step explanation:
x = -3 & 1; f(x) = 9
f(x) = a(x-r1)(x-r2)
f(0) = a(x-r1)(x-r2) = 9; 9 = a(0-(-3))(0-1)
9 = a(3)(-1); 9 = a(-3)
a = -3
f(x) = -3(x+3)(x-1)
Answer:
B
Step-by-step explanation:
The value of the 4 in 14.8 is 10 times the value of the 4 in 3.46.
Six nights.
1. Saturday night
2. Sunday night
3. Monday night
4. Tuesday night
5. Wednesday night
6. Thursday night
Given:
Total number of book = 22
Number of white books = 6
Number of Purple books = 9
Number of green books = 7
To find:
The probability that Warren takes out a green book in both draws (with replacement).
Solution:
We know that,




After replacement, the probability of event remains the same and the independent.
The probability that Warren takes out a green book in both draws is:



Therefore, the correct option is (a).