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alexira [117]
3 years ago
14

Convert the polar equation to rectangular form: r = 2 / [1 + sin(theta)]

Mathematics
1 answer:
iren2701 [21]3 years ago
8 0
R = 2 / (1 + sin <span>θ)

Using the following relations:

R = sqrt (x^2 + y^2)
sin </span>θ = y/R
<span>
R = 2 / (1 + y/R)
R</span>(1 + y/R<span>) = 2
</span><span>R + y = 2
R = 2 - y
sqrt(x^2 + y^2) = 2 - y

Squaring both sides:
x^2 + y^2 = (2 - y)^2
x^2 + y^2 = 4 - 4y + y^2

x^2 + 4y - 4 


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