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Orlov [11]
3 years ago
11

Tax rates are 10% on the first 10,000 you earn and 20% on amounts over that. You earn 15,000. What is your tax?

Mathematics
1 answer:
OleMash [197]3 years ago
8 0
This problem can be divided into two parts Part 1 - income up to $10,000 times 10% = $1,000 Part 2 - income over $10,000 = $15,000 - 10,000 = $5,000then, $5,000 times 20% = $1,000 Finally, $1,000 + 1,000 = $2,000
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Joe gave 1/4 of his total candies to his classmate then he gave 4/6 of when he had left to his brother when he went home then he
Makovka662 [10]

Answer:

112

Step-by-step explanation:

Given: Joe gave 1/4 of his total candies to his classmate.

            Then, he gave 4/6 of when he had left to his brother.

             He gave 25% of the remaining candies to his sister.

             Finally, he only had 21 candies left.

Lets assume the total number of candies at the beginning be "x".

First, finding the number candies left after giving candies to classmate.

∴ Remaining candies=  x- x\times \frac{1}{4}

Solving it to find remaining candies after giving candies to clasmate.

⇒ Remaining candies= x-\frac{x}{4}

Taking LCD as 4

⇒ Remaining candies= \frac{4x-x}{4} = \frac{3x}{4}

∴ Remaining candies after giving candies to clasmate= \frac{3x}{4}

now, finding the candies left after giving candies to his brother.

∴ Remaining candies= \frac{3x}{4} - \frac{3x}{4} \times \frac{4}{6}

Solving it to find the remaining candies after giving candies to his brother.

⇒ Remaining candies= \frac{3x}{4} - \frac{x}{2}

Taking LCD 4

⇒ Remaining candies= \frac{3x-2x}{4} = \frac{x}{4}

∴ Remaining candies after giving candies to his brother= \frac{x}{4}

We know, Joe was left with only 21 candies after giving candies to his sister.

Therefore, putting an equation for remaining candies to find the number of candies at the beginning.

⇒\frac{x}{4} - 25\% \times \frac{x}{4} = 21

⇒\frac{x}{4} - \frac{0.25x}{4} = 21

Taking LCD 4

⇒ \frac{x-0.25x}{4} = 21

⇒ \frac{0.75x}{4} = 21

Multiplying both side by 4

⇒0.75x= 21\times 4

dividing both side by 0.75

⇒x= \frac{21\times 4}{0.75}

∴x= 112

Hence, Joe had 112 candies at the beginning.

6 0
3 years ago
The LCM of two number is a multiple of 10 and 6. The two numbers are both less then 10.what is the LCM?
SCORPION-xisa [38]
This question doesn't make sense since the LCM of 10 and 6 is 30.

Hope i helped!!! :) 
4 0
4 years ago
PLEASE HELP ME ANSWER! im so desperate bro !!
sergey [27]

a)13

b) skewed

c) IQR

d)Sam's observation is correct

e)6.17

Step-by-step explanation:

Step 1 :

From the histogram we can infer that

0 to 2 texts has been sent by 1 student

2 to 4 texts has been sent by 3 student

4 to 6 texts has been sent by 4 student

6 to 8 texts has been sent by 4 student

8 to 10 texts has been sent by 5 student

Step 2:

a)

From step 1 , we can see that there are total of 17 students represented by the histogram

Step 3:

b)

This is a skewed histogram because we have all large values of students on the right of the histogram and smaller values on the left of the histogram.

In symmetrical histogram, there would be large values on the center and the smaller values on both sides.

Step 4:

c)

IQR would be better recommendation for this as this is a skewed histogram

Standard deviation would be recommended for a symmetrical histogram

Step 5:

d)

Total number of students is 17

Number of students who text between 8 to 10 messages is 5

Hence the students who text between 8 and 10 messages is 5/17

which is nearly 1/3 rd of the total students.

Hence Sam's observation is correct

Step 6:

e)

Mean amount of the texts = (1 * 3 + 3* 3 + 5*4 +7*4 + 9* 5) /17 = 6.17

6 0
3 years ago
A kangaroo hops 2 kilometers in 3 minutes. At this rate, how far does the kangaroo travel in 2 minutes? *
Dmitrij [34]

Answer:

At a speed of 2 km every 3 minutes, in 2 minutes the kangaroo would travel 1,333 km.

Step-by-step explanation:

If a kangaroo hops 2 kilometers in 3 minutes, to calculate how much distance this animal hops in 2 minutes, the following calculation should be performed:

2 km / 3 min = 0.666 km per minute (2/3 x 2)

0.666 km per minute x 2 minutes = 1.333 kilometers in 2 minutes (0.666 x 2)

Therefore, at a speed of 2 km every 3 minutes, in 2 minutes the kangaroo would hop 1,333 km.

5 0
3 years ago
True or false <br> The volume of a rectangular prism is always measured in cubic units?
Sindrei [870]

False

Step-by-step explanation:

yoijyngntintngngkgkgkkgnggf

3 0
3 years ago
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