Answer:
Probability that at least one of them will be affected = 3/16 + 3/16 + 1/16 = 7/16
Explanation:
If both parents are heterozygous for a genetic disease; Xx and Xx
The offspring's they will produce will be as follows ; XX, Xx, xX, xx
- Probability that first child will be affected = 1/4
- Probability that first child will not be affected = 1 - 1/4 = 3/4
- Probability that first child have it and second does not = 1/4 x 3/4 = 3/16
- Probability that first child does not have it, second child have it = 3/4 x 1/4 = 3/16
- Probability that both of them will have it = 1/4 x 1/4 = 1/16
- Hence, Probability that at least one of them will be affected = 3/16 + 3/16 + 1/16 = 7/16
Booking non-patients appointment are done directly from the schedule. one can make non-patient appointments such as meetings that are scheduled in the book application of the scheduling model. one can make non-patient appointments with or without patient in context on the name bar. it is possible to schedule non-patient appointment for multiple provider simultaneously.
Answer:
I believe it is A, but I could be wrong.
Explanation:
I think this, because when it says, "Other, less useful, versions of the genetic code were eliminated gradually throughout the course of evolution", I think it referencing to the fact that all animals and etc, are made up of common codes, and how over time, through evolution, certain codes were eliminated, because creatures were evolving.
Answer:
9:3:3:1
Explanation:
A dihybrid cross tracks two traits. Both parents are heterozygous, and one allele for each trait exhibits complete dominance *. This means that both parents have recessive alleles, but exhibit the dominant phenotype. The phenotype ratio predicted for dihybrid cross is 9:3:3:1. (There's a calculator on google that show the outcomes just to let ya know) hope it's correct .
Once a virus<span> infects one of your cells it begins to replicate. ... Both of them involve </span>invading<span> a cell called the host cell and reprogramming it to make copies ... proteins during entry and the </span>virus will<span> attach to the protein receptors on the </span>cell wall<span>.</span>
