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Zolol [24]
3 years ago
14

What is the equation of a line that has an x-intercept of -4 and a y-intercept of 8 ?

Mathematics
1 answer:
podryga [215]3 years ago
7 0

Answer:

y=2/-1+8

Step-by-step explanation:

  • -4= (-4,0) -4=x1 0=y1, 8= (0,8) 0=x2 8=y2
  • formula is, y2-y1/x2-x1
  • 8-0/0-4=8/-4=4/-2= 2/-1
  • 2/-1 is the slope or (m), use (-4,0) or (0,8) i used (0,8) because its easier.
  • (0,8), 0=x1 8=y1
  • formula is y-y1=m(x-x1)
  • y-8=2/-1(x-0) ---->distribute
  • y-8=2/-1x-0 --->get y alone

          +8          +8

  • so the answer is y=2/-1+8

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julia spends 2.25 on gas for her lawn mower.she earns 15.00 mowing her neighbors yard.what is julias profit?
Eduardwww [97]
This one is easy all you have to do is subtract the 2.25 by the 15 to get 12.75.
8 0
3 years ago
Read 2 more answers
(x + 5 1/2) 0.75= 5/8 What is x?
swat32
<span>(x + 5 1/2) 0.75= 5/8<span>
Convert 0.75 into a fraction
</span></span><span>(x + 5 1/2) 3/4= 5/8
Use distributive property
3/4x + 5 1/2*3/4 = 5/8
Convert 5 1/2 into improper fraction
3/4x + 11/2*3/4 = 5/8
Multiply
3/4x + 33/8 = 5/8
Subtract 33/8 from both sides
3/4x = 5/8 - 33/8
Subtract the numerators but NOT the denominators
3/4x = -28/8
Divide 3/4 on both sides
x = -28/8 divided by 3/4
Convert the division sign to multiplication while flipping the fraction 3/4 to 4/3
x = -28/8 * 4/3
Multiply
Final Answer: x = -112/24 or -4 16/24 or -4 4/6 or -4 2/3 *All answers are equivalent to each other.</span>
7 0
2 years ago
What is the width of a rectangle with length 5.5 cm and area 220 cm^2
Reika [66]
In the given question it is given that the length of the rectangle is 5.5 cm and the area of the rectangle is 220 cm^2.
Length of the rectangle = 5.5 cm
Area of the rectangle = 220 cm^2
Then we already know that
Area of a rectangle = Length * width
So Width of the rectangle = Area of the rectangle/ Length
                                           = 220/5.5
                                           = 2200/55
                                           = 40
So the width of the rectangle is 40 cm.<span>Hope  that you have got the answer you were looking for.

</span>


3 0
3 years ago
Work out the area of this circle. Give you answer in terms of pi and state it’s units
tino4ka555 [31]

Answer:

49π

Step-by-step explanation:

area of circle = πr^2

<em>Handy Tip: cherry pies delicious; apple pies are(R) too(2)! so C = πd and A = πr^2</em>

diameter = 14 cm

radius = 14/2 = 7cm

area of circle = π(7)^2

area of circle = 49π

Hope that helps!

3 0
3 years ago
Find all values of the angle θ (in radians, with 0 ≤ θ &lt; 2π) for which the matrix a = cos θ −sin θ sin θ cos θ has real eigen
harina [27]

The matrix

A=\begin{bmatrix}\cos\theta&-\sin\theta\\\sin\theta&\cos\theta\end{bmatrix}

has eigenvalues \lambda such that

\det(A-\lambda I)=\begin{vmatrix}\cos\theta-\lambda&-\sin\theta\\\sin\theta&\cos\theta-\lambda\end{vmatrix}=0

(\cos\theta-\lambda)^2+\sin^2\theta=0

(\cos\theta-\lambda)^2=-\sin^2\theta

\cos\theta-\lambda=\pm\sqrt{-\sin^2\theta}

\lambda=\cos\theta\pm\sqrt{-\sin^2\theta}

\sin^2\theta\ge0 for all values of \theta, so we need to have \sin\theta=0 in order for \lambda to be real-valued. This happens for

\sin\theta=0\implies\theta=n\pi

where n is any integer, and over the given interval we have \theta=0 and \theta=\pi.

4 0
3 years ago
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