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Zolol [24]
3 years ago
14

What is the equation of a line that has an x-intercept of -4 and a y-intercept of 8 ?

Mathematics
1 answer:
podryga [215]3 years ago
7 0

Answer:

y=2/-1+8

Step-by-step explanation:

  • -4= (-4,0) -4=x1 0=y1, 8= (0,8) 0=x2 8=y2
  • formula is, y2-y1/x2-x1
  • 8-0/0-4=8/-4=4/-2= 2/-1
  • 2/-1 is the slope or (m), use (-4,0) or (0,8) i used (0,8) because its easier.
  • (0,8), 0=x1 8=y1
  • formula is y-y1=m(x-x1)
  • y-8=2/-1(x-0) ---->distribute
  • y-8=2/-1x-0 --->get y alone

          +8          +8

  • so the answer is y=2/-1+8

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Sphere with a radius of a radius of 42 inches
prisoha [69]

Answer:

310339.1 in^3

Step-by-step explanation:

Volume=4/3*pi*r^3

Volume=4/3*pi*42^3

Volume=4/3*pi*74088

Volume=98784*pi

Volume=310339.0887

So the volume is about 310339.1 in^3

5 0
3 years ago
PLEASE HELP QUICK, I NEED IT
just olya [345]
We take the equation <span>d = -16t^2+12t</span> and subtract d from both sides to get
                                         0<span> = -16t^2+12t - d
We apply the quadratic formula to solve for t. With a = -16, b = 12, c = -d, we have
                                         t = [ -(12) </span><span>± √( 12^2 - 4(-16)(-d) ) ] / [2 * -16]</span>
                                           = [- 12 ± √(144-64d) ] / (-32)
                                           = [- 12 ± √16(9-4d)] / (-32)
                                           = [- 12 ± 4√(9-4d)] / (-32)
                                           = 3/8 ±√(9-4d) / 8
The answer to your question is t = 3/8 ±√(9-4d) / 8
5 0
3 years ago
Read 2 more answers
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FromTheMoon [43]

Answer:

1. B

2. Seven Hundred thousand nine hundred and four

Step-by-step explanation:

3 0
2 years ago
If the numbers -2.5, -1.6, -3 1/10, - 1/10, and -0.5 were graphed on a number line, which would appear farthest to the left?
Leona [35]
Turn the question around.
If all the numbers were positive: 2.5, 1.6, 3 1/10, 1/10, and 0.5, which would be farthest to the right?

The fact is that the negative numbers are a reflection of the positive numbers.
Since 3 1/10 would be farthest to the right with positive numbers, -3 1/10 will be farthest to the left with the negative numbers.

7 0
3 years ago
A solid is formed by adjoining two hemispheres to the ends of a right circular cylinder. An industrial tank of this shape must h
mestny [16]

Answer:

Radius =6.518 feet

Height = 26.074 feet

Step-by-step explanation:

The Volume of the Solid formed  = Volume of the two Hemisphere + Volume of the Cylinder

Volume of a Hemisphere  =\frac{2}{3}\pi r^3

Volume of a Cylinder =\pi r^2 h

Therefore:

The Volume of the Solid formed

=2(\frac{2}{3}\pi r^3)+\pi r^2 h\\\frac{4}{3}\pi r^3+\pi r^2 h=4640\\\pi r^2(\frac{4r}{3}+ h)=4640\\\frac{4r}{3}+ h =\frac{4640}{\pi r^2} \\h=\frac{4640}{\pi r^2}-\frac{4r}{3}

Area of the Hemisphere =2\pi r^2

Curved Surface Area of the Cylinder =2\pi rh

Total Surface Area=

2\pi r^2+2\pi r^2+2\pi rh\\=4\pi r^2+2\pi rh

Cost of the Hemispherical Ends  = 2 X  Cost of the surface area of the sides.

Therefore total Cost, C

=2(4\pi r^2)+2\pi rh\\C=8\pi r^2+2\pi rh

Recall: h=\frac{4640}{\pi r^2}-\frac{4r}{3}

Therefore:

C=8\pi r^2+2\pi r(\frac{4640}{\pi r^2}-\frac{4r}{3})\\C=8\pi r^2+\frac{9280}{r}-\frac{8\pi r^2}{3}\\C=\frac{9280}{r}+\frac{24\pi r^2-8\pi r^2}{3}\\C=\frac{9280}{r}+\frac{16\pi r^2}{3}\\C=\frac{27840+16\pi r^3}{3r}

The minimum cost occurs at the point where the derivative equals zero.

C^{'}=\frac{-27840+32\pi r^3}{3r^2}

When \:C^{'}=0

-27840+32\pi r^3=0\\27840=32\pi r^3\\r^3=27840 \div 32\pi=276.9296\\r=\sqrt[3]{276.9296} =6.518

Recall:

h=\frac{4640}{\pi r^2}-\frac{4r}{3}\\h=\frac{4640}{\pi*6.518^2}-\frac{4*6.518}{3}\\h=26.074 feet

Therefore, the dimensions that will minimize the cost are:

Radius =6.518 feet

Height = 26.074 feet

5 0
2 years ago
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