444.44 i think hope this helps
A
given that y varies directly as x, then the relationship is
y = kx ← k is the constant of variation
To find k use the given condition x = 3 when y = 24
y = kx ⇒ k =
=
= 8
y = 8x
Answer:
It's A.
Step-by-step explanation:
I took the test
Answer:
200
Step-by-step explanation:
170% of x = 680
Set up an equation:
170/100 • x/1 = 680
1.7 • x = 680
1.7x = 680
x = 400
50% of 400
1/2 • 400 = 200
Answer:
The largest total area that can be enclosed will be a square of length 272 yards.
Step-by-step explanation:
First we get the perimeter of the large rectangular enclosure.
Perimeter of a rectangle =2(l + w)
Perimeter of the large rectangular enclosure= 1088 yard
Therefore:
2(L+W)=1088
The region inside the fence is the area
Area: A = LW
We need to solve the perimeter formula for either the length or width.
2L+ 2W= 1088 yd
2W= 1088– 2L
W = 
W = 544–L
Now substitute W = 544–L into the area formula
A = LW
A = L(544 – L)
A = 544L–L²
Since A is a quadratic expression, we re-write the expression with the exponents in descending order.
A = –L²+544L
Next, we look for the value of the x coordinate


L=272 yards
Plugging L=272 yards into the calculation for area:
A = –L²+544L
A(272)=-272²+544(272)
=73984 square yards
Thus the largest area that could be encompassed would be a square where each side has a length of 272 yards and a width of:
W = 544 – L
= 544 – 272
= 272 yards