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Zigmanuir [339]
3 years ago
12

A certain radio wave has a frequency of 2.0 x 10^6 Hz. What is its wavelength?

Physics
1 answer:
den301095 [7]3 years ago
4 0
Solution:  
Formula for finding wavelength from frequency is wavelength=wave velocity(c)/frequency(f). 
 General value of Wave velocity (c) = 3 x 10^8 m/s
 Given frequency = 2.0 x 10^6 Hz 
 Now,
 Wavelength = 3 x 10^8 m/s / 2.0 x 10^6 Hz
  = 150 m
 Therefore the value of wavelength is 150m.
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Which of the following statements are true about gravity?
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D. C. B... A is incorrect because gravity exists everywhere in the known universe, as long as you're not in between celestial bodies.
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4 years ago
A block of wood of mass 24 kg floats on water. The volume of the block below the surface of the water and the density of the woo
Slav-nsk [51]

Answer:

0.024m^3

Explanation:

=======

Answer:

=======

Given:-

Mass of the block of wood = 24 kg

Volume of wood = 0.032 m^3

Density of water = 1000kg/m^3

Now,

Density of wood is given by,

\frac{m}{v} = \frac{24}{0.032} \\

\frac{m}{v} = 750 \: kg/m ^{3}

Therefore,

The density of wood is 750kg/m^3

By principle of floatation,

Mass \:of\: wood = Mass\: of\: liquid \:displaced

Therefore,

Mass of liquid displaced = 24kg

Volume of liquid displaced (v),

\frac{m}{v} = \frac{24}{1000} \\

\frac{m}{v} = 0.24m ^{3}

Now,

Since the volume of the wood is equal to the volume of water displaced, it is 0.024m^3

=====

Note:

=====

=> The volume of the wood below the water surface is the volume of water displaced.

=> Buoyant\: force = Weight\: of\: the \:displaced\: water.

8 0
3 years ago
A conducting sphere with radius R is charged until the magnitude of the electric field just outside its surface is E. The electr
dusya [7]

Answer:

he correct answer is V = ER

Explanation:

In this exercise they give us the electric field on the surface of the sphere and ask us about the electric potential, the two quantities are related

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where E is the elective field and normal displacement vector.

Since E is radial in a spray the displacement vector is also radial, the dot product e reduces to the algebraic product.

                 ΔV = ∫ E ds

                 ΔV = E s

                 

since s is in the direction of the radii its value on the surface of the spheres s = R

                  ΔV = E R

checking the correct answer is V = ER

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Answer:

50 Mph.

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