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3 years ago

When can a high speed velocity cause damage?'

Physics

1 answer:

sweet-ann [11.9K]3 years ago

7 0

Answer:

50 Mph.

Explanation:

According to the National Severe Storms Laboratory, winds can really begin to cause damage when they reach 50 mph. But here’s what happens before and after they reach that threshold, according to the Beaufort Wind Scale (showing estimated wind speeds): - at 19 to 24 mph, smaller trees begin to sway.

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A small car with mass of 0.800 kg travels at a constant speed

Alexandra [31]

Answer:

The equation of equilibrium at the top of the vertical circle is:

\Sigma F = - N - m\cdot g = - m \cdot \frac{v^{2}}{R}

The speed experimented by the car is:

\frac{N}{m}+g=\frac{v^{2}}{R}

v = \sqrt{R\cdot (\frac{N}{m}+g) }

v = \sqrt{(5\,m)\cdot (\frac{6\,N}{0.8\,kg} +9.807\,\frac{kg}{m^{2}} )}

v\approx 9.302\,\frac{m}{s}

The equation of equilibrium at the bottom of the vertical circle is:

\Sigma F = N - m\cdot g = m \cdot \frac{v^{2}}{R}

The normal force on the car when it is at the bottom of the track is:

N=m\cdot (\frac{v^{2}}{R}+g )

N = (0.8\,kg)\cdot \left(\frac{(9.302\,\frac{m}{s} )^{2}}{5\,m}+ 9.807\,\frac{m}{s^{2}} \right)

N=21.690\,N

7 0

3 years ago

1. What are three questions you should ask before joining a club?

lara [203]

Answer:

what time does it start.

what do I need to join.

what are your expectations.

7 0

3 years ago

A physical pendulum in the form of a planar object moves in simple harmonic motion with a frequency of 0.680 Hz. The pendulum ha

sineoko [7]

Answer:

Therefore, the moment of inertia is:

$I=0.37 \: kgm^{2}$

Explanation:

The period of an oscillation equation of a solid pendulum is given by:

$T=2\pi \sqrt{\frac{I}{Mgd}}$ (1)

Where:

I is the moment of inertia
M is the mass of the pendulum
d is the distance from the center of mass to the pivot
g is the gravity

Let's solve the equation (1) for I

$T=2\pi \sqrt{\frac{I}{Mgd}}$

$I=Mgd(\frac{T}{2\pi})^{2}$

Before find I, we need to remember that

$T = \frac{1}{f}=\frac{1}{0.680}=1.47\: s$

Now, the moment of inertia will be:

$I=2*9.81*0.340(\frac{1.47}{2\pi})^{2}$

Therefore, the moment of inertia is:

$I=0.37 \: kgm^{2}$

I hope it helps you!

7 0

3 years ago

A 350-g mass is attached to a spring whose spring constant is 64 N/m. Its maximum acceleration is 5.3 m/s2. What is the frequenc

max2010maxim [7]

The frequency of oscillation is 2.153 Hz

What is the frequency of spring?

Spring Frequency is the natural frequency of spring with a weight at the lower end. Spring is fixed from the upper end and the lower end is free.

For the mass-spring system in this problem,

The Frequency of spring is calculated with the equation:

$f = \frac{1}{2\pi } \sqrt{\frac{k}{m} }$

Where,

f = frequency of spring

k = spring constant = 64 N/m

m = mass attached to spring = 350g = 0.350 kg

a = maximum acceleration = 5.3 m/s^2

Substituting the values in the equation,

$f = \frac{1}{2\pi } \sqrt{\frac{64}{0.350} }$

$f = \frac{1}{2\pi } ( 13.522)$

$f = 2.1535 Hz$

Hence,

The frequency of oscillation is 2.153 Hz

Learn more about frequency here:

brainly.com/question/13978015

#SPJ4

6 0

2 years ago

the electron are accelrated to a speed of 2.40*10^7 in 1.8*10^-9, the force experinced by an electron ?

dalvyx [7]

Force = mass × acceleration

To find acceleration, we can divide the speed by the time it took:

acceleration = 2.40×10^7 / 1.8×10^-9

acceleration = 1.33×10^16

the mass is equal to the mass of an electron

force = (9.11×10^-31)(1.33×10^16)

force = 1.21×10^-14 N

3 0

3 years ago