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BartSMP [9]
2 years ago
11

When can a high speed velocity cause damage?'

Physics
1 answer:
sweet-ann [11.9K]2 years ago
7 0

Answer:

50 Mph.

Explanation:

According to the National Severe Storms Laboratory, winds can really begin to cause damage when they reach <em><u>50 mph</u></em>. But here’s what happens before and after they reach that threshold, according to the Beaufort Wind Scale (showing estimated wind speeds): - at 19 to 24 mph, smaller trees begin to sway.

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Nicole throws a ball straight up. Chad watches the ball from a window 6.10m above the point where Nicole released it. The ball p
solong [7]

Answer:

v=16.234m/s

Explanation:

Given data

Distance S=6.10 m

Initial Speed u=12.0 m/s

To find

Final Speed v

Solution

From third equation of motion we know that:

v^{2}-u^{2}=2aS

where

v is final velocity

u is initial velocity

a is acceleration

S is distance

Substitute the given values to find v

v^{2}=u^{2}+2aS\\v^{2}=(12.0m/s)^{2} +2(9.8m/s^{2} )(6.10m)\\v^{2}=263.56\\  v=\sqrt{263.56}\\ v=16.234m/s

3 0
3 years ago
What is the RMS speed of Helium atoms when the temperature of the Helium gas is 206.0 K? (Possibly useful constants: the atomic
saw5 [17]

Answer:

a)1.13×10³

b)1.6×10³

Explanation:

Given:

Boltzmann's constant (K)=1.38×10^-23 J/K

atmoic mass of helium = 4 AMU or 4×1.66×10^-27kg

a)The formula for RMS speed (Vrms) is given as

Vrms=\sqrt{\frac{3KT}{m} }

where

K= Boltzmann's constant

T= temperature

m=mass of the gas

Vrms=\sqrt{\frac{3\times 1.38\times 10^{-23}\times 206}{6.64\times 10^{-27}}}

Vrms=1.13\times 10^{3}m/s

b) RMS speed of helium when the temperature is doubled

Vrms=\sqrt{\frac{3\times 1.38\times 10^{-23}\times 2\times 206}{6.64\times 10^{-27}}}

Vrms=1.598\times 10^{3}m/s

4 0
3 years ago
Read 2 more answers
Compared to that of a plane on the ground, Earth’s gravitational pull on a plane 7 miles above Earth is approximately A) zero. B
NeTakaya
I am proply right that it is B
7 0
3 years ago
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A small car with mass of 0.800 kg travels at a constant speed
Alexandra [31]

Answer:

The equation of equilibrium at the top of the vertical circle is:

\Sigma F = - N - m\cdot g = - m \cdot \frac{v^{2}}{R}

The speed experimented by the car is:

\frac{N}{m}+g=\frac{v^{2}}{R}

v = \sqrt{R\cdot (\frac{N}{m}+g) }

v = \sqrt{(5\,m)\cdot (\frac{6\,N}{0.8\,kg} +9.807\,\frac{kg}{m^{2}} )}

v\approx 9.302\,\frac{m}{s}

The equation of equilibrium at the bottom of the vertical circle is:

\Sigma F = N - m\cdot g = m \cdot \frac{v^{2}}{R}

The normal force on the car when it is at the bottom of the track is:

N=m\cdot (\frac{v^{2}}{R}+g )

N = (0.8\,kg)\cdot \left(\frac{(9.302\,\frac{m}{s} )^{2}}{5\,m}+ 9.807\,\frac{m}{s^{2}} \right)

N=21.690\,N

7 0
2 years ago
Reaction time is the lapse of time between muscular movement and external stimuli. True or false
riadik2000 [5.3K]
False. reaction time would be lapse of time between external stimuli and muscular movement
3 0
3 years ago
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