The "x-interept" is the point where the graph crosses the x-axis.
From here, it looks like this graph crosses the x-axis where x=2 .
So the point is <em>(2, 0)</em> .
That's choice-<em>A</em> .
This isnt a question its just all numbers and inches what did u want to get from that?
The horizontal asymptote of the function is the minimum number of deer in the area.
- The equation of horizontal asymptote is:

- The horizontal asymptote means that, the number of deer will never be less than 40
The equation is given as:

Expand the numerator

Cancel out the common factor

Hence, the equation of horizontal asymptote is:

The horizontal asymptote means that, the number of deer will never be less than 40
Read more about horizontal asymptotes at:
brainly.com/question/4084552
Answer:
Quadratic Equation:


From the standard form of a Quadratic Function, we get:

Discriminant:



From the discriminant, we conclude that the equation will have two real solutions.
State that:



By the way, solving the equation given:




