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MatroZZZ [7]
3 years ago
14

Sarah is training for a bike race. She rides her bike 5 3/4 miles in 1/3 hour.What is Sarah's rate miles per hour?

Mathematics
2 answers:
anyanavicka [17]3 years ago
6 0

Answer:

Step-by-step explanation:

Answer:

Sarah's rate is 17 \frac{1}{4} miles per hour.

Step-by-step explanation:

we can use proportion to solve this;

Let x represent sarah's rate miles per hour

5 3/4 miles = 1/3 hour

    x             = 1 hour

cross-multiply

5 3/4  = 1/3 x

but 5 3/4 =\frac{23}{4}

\frac{23}{4}  =  \frac{x}{3}

cross- multiply

4x = 23× 3

4x =69

Divide both-side of the equation by 4

\frac{4x}{4} = \frac{69}{4}

(On the left-hand side of the equation, 4 at the numerator will cancel-out 4 at the denominator while on the right-side of the equation 69 will be divided by 4)

x  =  17 \frac{1}{4} miles

Therefore Sarah's rate is 17 \frac{1}{4} miles per hour.

Alik [6]3 years ago
4 0

Answer:17 1/4 miles per hour  



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A rectangle patio has a length four times its width. It also has a 3-ft wide brick boarder around it. Write a quadratic function
Margarita [4]

Answer: Area = 4w² + 30w + 36

Step-by-step explanation:

Let w represent the width of the rectangular patio.

The rectangle patio has a length four times its width. It means that the length of the patio is 4w.

The formula for determining the area of a rectangle is expressed as

Area = length × width

If the boarder is 3 ft, the combined length of the patio and the boarder would be (4w + 3 + 3) = (4w + 6) feet

Also, the combined width of the patio and the boarder would be

(w + 3 + 3) = (w + 6) feet

Therefore, the expression for the area of the patio and boarder is

Area = (4w + 6)(w + 6)

Area = 4w² + 24w + 6w + 36

Area = 4w² + 30w + 36

5 0
4 years ago
During the sale Mr.Hansen purchased a coat for 60% off the regular price. The coat normally sold for $220. How much money did he
Inessa [10]

Answer:

$132

Step-by-step explanation:

220/100 is 2.2

2.2 times 60 is 132

He saved 132 dollars

3 0
3 years ago
A bottle and a cap together cost $1.10. The bottle costs $1 more than the cap. How much does each cost?
Darya [45]

Answer:

The cap costs 10 cents and the botttle costs $1

Step-by-step explanation:

1.10-1=.10

3 0
3 years ago
Find the interquartile range for a data set having the five-number summary: 3.4, 10.8, 16.7, 23.1, 31.5
natita [175]

.Answer:

D. 12.3

Step-by-step explanation:

Arrange the data in increasing order

3.4, 10.8, 16.7, 23.1, 31.5

⇒This is an odd set of numbers, to find the interquartile range you include the median in both quartiles.

Locate the median/center value

3.4, 10.8, 16.7, 23.1, 31.5

Find lower half and find the median

lower half values⇒3.4, 10.8, 16.7

Median=Q1=10.8

Find the upper half and find

upper half= 16.7,23.1, 31.5

median= 16.7,23.1,31.5

Q3=23.1

Interquartile range=Q3-Q1

23.1-10.8=12.3

5 0
3 years ago
What is the difference between arcsin and sin^-1 ?
Len [333]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2094473

_______________


Both refer to the inverse sine function.

The inverse sine (or arcsine) of x:

\mathsf{f(x)=arcsin(x)=sin^{-1}(x)}


where x is a real number in the domain of the function:

\mathsf{-1\le x\le 1}


and the arcsine function returns an angle in the interval  \mathsf{\left[-\,\frac{\pi}{2},\,\frac{\pi}{2}\right]:}

\mathsf{-\,\dfrac{\pi}{2}\le arcsin(x)\le \dfrac{\pi}{2}}\quad\longleftarrow\quad\textsf{range of the inverse sine function.}


So if you see anywhere one of these expressions below

\mathsf{\theta=arcsin(x)~~or~~\theta=sin^{-1}(x)}


then you should look for an angle \theta that satisfies the following conditions:

\footnotesize\begin{array}{l}\bullet\end{array}\normalsize\begin{array}{l}\mathsf{sin\,\theta=x;} \end{array}\\\\\\
\footnotesize\begin{array}{l}\bullet\end{array}\normalsize\begin{array}{l}\mathsf{\dfrac{\pi}{2} \le \theta\le\dfrac{\pi}{2}.} \end{array}


This angle \theta is called the inverse sine of the real number x.

______


Pay attention and do not mistake the arcsine function for the reciprocal of sine (which is cosecant); especially if you prefer or see that notation with an superscript -1. This one can be easily mistaken for an exponent:

\mathsf{sin^{-1}(x)=arcsin(x)\qquad\quad\checkmark}


but the reciprocal is something like

\mathsf{\big[sin(x)\big]^{-1}=\dfrac{1}{sin\,(x)}=csc(x)\qquad\quad(!!)}

and this last one has a total different meaning.


I hope this helps. =)

6 0
4 years ago
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