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KIM [24]
3 years ago
9

Please explain your answers and I'll mark the Brainliest!

Mathematics
2 answers:
Readme [11.4K]3 years ago
8 0

Answer:

The answer is B.

Step-by-step explanation:

As the sum of interior angles in a triangle is 180deg.

<C = 180-110-45 = 25deg.

Using sine rule, a/sinA = b/sinB = c/sinC

a=7*sin45deg/sin25deg = 11.71

b=7*sin110deg/sin25deg = 15.56

The answer is B.

guajiro [1.7K]3 years ago
4 0

B) a = 11.71 and b = 15.56 is the correct answer.

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Need help on my math work here is a pic of the question
faltersainse [42]

Answer:

-3

Step-by-step explanation:

A = midpoint

-17 + 5 = -12

-12/2 = -6 = A

-6 + 0 = -6

-6/2 = -3 = B

8 0
2 years ago
Read 2 more answers
What type of simple machine is a vise and what does it do also what is a crow bar
mel-nik [20]
A crow bar is a bar that help you lift thing up
4 0
3 years ago
Simplify 8.9 - 1.4x + (-6.5x) + 3.4
lesya692 [45]

Answer:

12.3 - 7.9x

Step-by-step explanation:

8.9 - 1.4x + (-6.5) +3.4

12.3 - 1.4x - 6.5=

12.3 - 7.9x

8 0
3 years ago
1948 Olympics
mash [69]

Answer:

For 1948 Men's :Interquartile range is 1.5, Median is 58.3

For 2012 Men's: Interquartile range is 0.315, Median is 47.86

You can infer that in 2012 the swimmers were better and it was more competitive as the interquartile range was lower and the median was also lower as well

Step-by-step explanation:

1948 Men's 100m

57.3, 57.8, 58.1, 58.3, 58.3, 59.3, 59.6,1:00.5

               ⬆                ⬆                 ⬆

         Low IQR      Median       High IQR

Low IQR is average of 57.8 and 58.1 = 57.95

High IQR  is average of 59.3 and 59.6 =  59.45

Median is average of 58.3 and 58.3 = 58.3

Interquartile range is High IQR- Low IQR

59.45 - 57.95=1.5

2012 Men's 100m

47.52, 47.53, 47.8, 47.84, 47.88, 47.92, 48.04, 48.44

                    ⬆                  ⬆                      ⬆

             Low IQR         Median          High IQR

Low IQR is average of 47.53 and 47.8 = 47.665

High IQR is average of 48.04 and 47.92 = 47.98

Median is average of 47.88 and 47.84 = 47.86

Interquartile range is High IQR-Low IQR

47.98-47.665=0.315

Read more on Brainly.com - brainly.com/question/14915771#readmore

8 0
4 years ago
84. Use properties of exponents to rewrite each expression with only positive, rational exponents. Then find the numerical value
Yakvenalex [24]

Answer:

a) 1/27

b) 16

c) 1/8

Step-by-step explanation:

a) x^{-3/2}

One of the properties of the exponents tells us that when we have a negative exponent we can express it in terms of its positive exponent by turning it into the denominator (and changing its sign), so we would have:

x^{-3/2}=\frac{1}{x^{3/2} }

And now, solving for x = 9 we have:

\frac{1}{x^{3/2}}=\frac{1}{9^{3/2} }  =\frac{1}{27}

b) y^{4/3}

This is already a positive rational exponent so we are just going to substitute the value of y = 8 into the expression

y^{4/3}=8^{4/3}=16

c) z^{-3/4}

Using the same property we used in a) we have:

z^{-3/4}=\frac{1}{z^{3/4} }

And now, solving for z = 16 we have:

\frac{1}{z^3/4} } =\frac{1}{16^{3/4} } =\frac{1}{8}

4 0
3 years ago
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