Answer:
the hawk has flow 824.62 meters southwest of the mountain peak.
Step-by-step explanation:
In order to find the distance we need to use the Pythagoras theorem
d^2 = 800^2 + 200^2
d= 824.6 m
we can find the direction by using the eq for a tangent
he opposite side is 200 m and the adjacent side is 800m
tan theta = opposite / adjacent
theta = arc tan (800/200)
The hawk is at a distance of 824.6m flying at an angle 76 degrees NE of the mountain peak.
The final location will be southwest of the mountain peek.
a2+b2=c2
a = 200
b= 800
c = √(2002+8002) = 824.62
So the hawk has flow 824.62 meters southwest of the mountain peak.
Answer:
4
1×2=2×2=4 so that is how the answer is reached
Answer:
A = 222 units^2
Step-by-step explanation:
To find the area of this trapezoid, first draw an imaginary horizontal line parallel to AD and connecting C with AB (Call this point E). Below this line we have the triangle CEB with hypotenuse 13 units and vertical side (21 - 16) units, or 5 units. Then the width of the entire figure shown can be obtainied using the Pythagorean Theorem:
(5 units)^2 + CE^2 = (13 units)^2, or 25 + CE^2 = 169. Solving this for CE, we get |CE| = 12.
The area of this trapezoid is
A = (average vertical length)(width), which here is:
(21 + 16) units
A = --------------------- * (12 units), which simplifies to:
2
A = (37/2 units)(12 units) = A = 37*6 units = A = 222 units^2
Positive. Keyword is 'above' zero meaning positive numbers. Negative would be 'below' zero.
