The information given about the proof does that Daniel made an error on line 2.
<h3>How to illustrate the information?</h3>
Given:
1. AB = 3x +2; BC = 4x + 8; AC = 38
2. AB + BC = AC incorrect (not an angle angle addition postulate)
3. 3x+2 + 4x + 8 = 38 correct
4. 7x + 10 = 38 correct
5. 7x = 28 correct
6. x = 4
Daniel made an error on line 2.
Here is the complete question:
Daniel wrote the following two-column proof for the given information. Given: AB = 3x + 2; BC = 4x + 8; AC = 38 Prove: x = 4 Statements Reason 1. AB = 3x + 2; BC = 4x + 8; AC = 38 1. Given 2. AB + BC = AC 2. Angle Addition Postulate 3. 3x + 2 + 4x + 8 = 38 3. Substitution Property of Equality 4. 7x + 10 = 38 4. Combining Like Terms 5. 7x = 28 5. Subtraction Property of Equality 6. x = 4 6. Division Property of Equality On which line, did Daniel make his error? line 2 line 3 line 4 line 5
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-30-27= -57
When both numbers are negative, they are “added” in a sense, but remain negative.
-5-(-4)= -1
You have to multiply the (-4) by the “invisible” -1 on the outside before you add/subtract.
The answer is: x² – 6x + 9 = 0 .
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Explanation:
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Given: (x – 3)² = 0 ; write as: general form: "ax² + bx + c = 0"; a ≠ 0 .
<span>
Note: </span>(x – 3)² = (x – 3)(x – 3) = x² – 3x – 3x + 9 = x² – 6x + 9 ;
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Rewrite: (x – 3)² = 0 ; →
as: x² – 6x + 9 = 0 ; which is our answer.
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→ x² – 6x + 9 = 0 ; is in "general form", or "standard equation format"; that is: " ax² + bx + c = 0 "; (a ≠ 0) ;
→ in which:
a = 1 (implied coefficient, since anything multiplied by "1" is that same value);
b = -6;
c = 9
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The fraction is one whole aka one
Answer:
P(7, -7)
Step-by-step explanation:
Xp = 6+ ⅓(9-6)= 6+ ⅓(3)=6+1 =7
Yp = -10 + ⅓(-1+10)= -10+⅓(9)= -10+3=-7
=> P (7, -7)
