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4 years ago

Graph the solution of the inequality. -4 < 2t < 2 PLZ HELP NOW

Mathematics

2 answers:

Ludmilka [50]4 years ago

4 0

Answer:

Firstly you have to divide by 2 to get 't' so -4/2=-2

2/2=1

so the simplified inequality= -2<t<1

< and > are both illustrated as hollow circles so on a number line put a hollow circle on -2 and 1 and attach with a line

oee [108]4 years ago

3 0

Answer:

Step-by-step explanation:

-4<= 2t <2

-4/2<= t <2/2

-2<= t <1

(Its touches -2 but doesnt touch 1)

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The battery on McKenzies old computer can last 4(1/5) hours. She bought a new computer that has a battery that can last 40% long

Solnce55 [7]

Answer:

$5\frac{22}{25}\ hours$

Step-by-step explanation:

we know that

$4\frac{1}{5}\ hours=\frac{4*5+1}{5}=\frac{21}{5}\ hours$

$100\%+40\%=140\%=\frac{140}{100}$

Let

x ------> new battery life

The equation that represent this situation is

$x=\frac{140}{100} (\frac{21}{5})=\frac{2,940}{500}\ hours$

convert to mixed number

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4 0

3 years ago

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arsen [322]

Answer:

1.)B

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3 0

3 years ago

An airplane travels 6111 kilometers against the wind in 9 hours and 7911 kilometers with the wind in the same amount of time. Wh

natima [27]

Answer:

Speed of the plane in still air: $779\; {\rm km \cdot h^{-1}}$ .

Windspeed: $100\; {\rm km \cdot h^{-1}}$ .

Step-by-step explanation:

Assume that $x\; {\rm km \cdot h^{-1}}$ is the speed of the plane in still air, and that $y\; {\rm km \cdot h^{-1}}$ is the speed of the wind.

When the plane is travelling against wind, the ground speed of this plane (speed of the plane relative to the ground) would be $(x - y)\; {\rm km \cdot h^{-1}}$ .
When this plane is travelling in the same direction as the wind, the ground speed of this plane would be $(x + y)\; {\rm km \cdot h^{-1}}$ .

The question states that when going against the wind ( $v = (x - y)\; {\rm km \cdot h^{-1}}$ ,) the plane travels $6111\; {\rm km}$ in $9\; {\rm h}$ . Hence, $9\, (x - y) = 6111$ .

Similarly, since the plane travels $7911\; {\rm km}$ in $9\; {\rm h}$ when travelling in the same direction as the wind ( $v = (x + y)\; {\rm km \cdot h^{-1}}$ ,) $9\, (x + y) = 7911$ .

Add the two equations to eliminate $y$ . Subtract the second equation from the first to eliminate $x$ . Solve this system of equations for $x$ and $y$ : $x = 779$ and $y = 100$ .

Hence, the speed of this plane in still air would be $779\; {\rm km \cdot h^{-1}}$ , whereas the speed of the wind would be $100\; {\rm km \cdot h^{-1}}$ .

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2 years ago

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Scorpion4ik [409]

Answer:

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Step-by-step explanation:

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3 years ago

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AlekseyPX

Answer:

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Step-by-step explanation:

→ State the formula

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8 × 2 × 5

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2 years ago