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Sedbober [7]
3 years ago
10

Graph the solution of the inequality. -4 < 2t < 2 PLZ HELP NOW

Mathematics
2 answers:
Ludmilka [50]3 years ago
4 0

Answer:

Firstly you have to divide by 2 to get 't' so -4/2=-2

2/2=1

so the simplified inequality= -2<t<1

< and > are both illustrated as hollow circles so on a number line put a hollow circle on -2 and 1 and attach with a line

oee [108]3 years ago
3 0

Answer:

B

Step-by-step explanation:

-4<= 2t <2

-4/2<= t <2/2

-2<= t <1

(Its touches -2 but doesnt touch 1)

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Factor the expression by finding the GCF.
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Answer:

4m(4m-3)

Step-by-step explanation:

Factor 4m out of the statement because 4 is a factor of both 16 and -12, and m is a factor in m^2 and m.

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What is the area of the partial circle with a radius of 8 cm? Use 3. 14 for pi.
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What is 5/36 converted to decimal
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0.1389. 5 decided by 36 in a calc
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A simple random sample of size nequals10 is obtained from a population with muequals68 and sigmaequals15. ​(a) What must be true
valentina_108 [34]

Answer:

(a) The distribution of the sample mean (\bar x) is <em>N</em> (68, 4.74²).

(b) The value of P(\bar X is 0.7642.

(c) The value of P(\bar X\geq 69.1) is 0.3670.

Step-by-step explanation:

A random sample of size <em>n</em> = 10 is selected from a population.

Let the population be made up of the random variable <em>X</em>.

The mean and standard deviation of <em>X</em> are:

\mu=68\\\sigma=15

(a)

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we take appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

Since the sample selected is not large, i.e. <em>n</em> = 10 < 30, for the distribution of the sample mean will be approximately normally distributed, the population from which the sample is selected must be normally distributed.

Then, the mean of the distribution of the sample mean is given by,

\mu_{\bar x}=\mu=68

And the standard deviation of the distribution of the sample mean is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{15}{\sqrt{10}}=4.74

Thus, the distribution of the sample mean (\bar x) is <em>N</em> (68, 4.74²).

(b)

Compute the value of P(\bar X as follows:

P(\bar X

                    =P(Z

*Use a <em>z</em>-table for the probability.

Thus, the value of P(\bar X is 0.7642.

(c)

Compute the value of P(\bar X\geq 69.1) as follows:

Apply continuity correction as follows:

P(\bar X\geq 69.1)=P(\bar X> 69.1+0.5)

                    =P(\bar X>69.6)

                    =P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}}>\frac{69.6-68}{4.74})

                    =P(Z>0.34)\\=1-P(Z

Thus, the value of P(\bar X\geq 69.1) is 0.3670.

7 0
3 years ago
What is the value of the x?
Ronch [10]

Answer:

53

Step-by-step explanation:

37+90=127

180-127=53

7 0
3 years ago
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