Hello!
The general chemical equation for the neutralization of an acid HA with NaOH is the following:
HA(aq) + NaOH(aq) → NaA(aq) + H₂O(l)
For determining the concentration of the acid solution, we can use the equation shown below:
![moles HA=moles NaOH \\ \\ cHA*VHA=cNaOH*VNaOH \\ \\ cHA= \frac{cNaOH*vNaOH}{VHA}= \frac{0,5M*25,1 mL}{35 mL}=0,36 M](https://tex.z-dn.net/?f=moles%20HA%3Dmoles%20NaOH%20%5C%5C%20%20%5C%5C%20cHA%2AVHA%3DcNaOH%2AVNaOH%20%5C%5C%20%20%5C%5C%20cHA%3D%20%5Cfrac%7BcNaOH%2AvNaOH%7D%7BVHA%7D%3D%20%5Cfrac%7B0%2C5M%2A25%2C1%20mL%7D%7B35%20mL%7D%3D0%2C36%20M%20%20)
So, the concentration of the Acid is
0,36 MHave a nice day!
Answer:
The rate of flow of nitrogen into the reactor is 2,470.588 kg/h.
Explanation:
Mole percentage of nitrogen gas = 25 mole%
Mole percentage of hydrogen gas = 75 mole%
Average molecular weight of the mixture:
![(0.25\times 28 g/mol)+(0.75\times 2 g/mol)=8.5 g/mol](https://tex.z-dn.net/?f=%280.25%5Ctimes%2028%20g%2Fmol%29%2B%280.75%5Ctimes%202%20g%2Fmol%29%3D8.5%20g%2Fmol)
Rate of flow of the stream = 3000 kg/h
Mass of stream in 1 hour = 3000 kg = 3,000,000 g
Moles of stream :
![\frac{3000 g}{8.5 g/mol}=352,941.17 mol](https://tex.z-dn.net/?f=%5Cfrac%7B3000%20g%7D%7B8.5%20g%2Fmol%7D%3D352%2C941.17%20mol)
Moles of nitrogen gas in 352,941.17 moles of stream be x
![25\%=\frac{\text{Moles of nitrogen gas}}{\text{Moles of stream}}\times 100](https://tex.z-dn.net/?f=25%5C%25%3D%5Cfrac%7B%5Ctext%7BMoles%20of%20nitrogen%20gas%7D%7D%7B%5Ctext%7BMoles%20of%20stream%7D%7D%5Ctimes%20100)
![25=\frac{x}{352,941.17mol}\times 100](https://tex.z-dn.net/?f=25%3D%5Cfrac%7Bx%7D%7B352%2C941.17mol%7D%5Ctimes%20100)
x = 88,235.294 mol
Mass of 8,823,529.4 mole of nitrogen gas:
![88235.294 mol\times 28 g/mol=2.470588.2 g=2,470.588 kg](https://tex.z-dn.net/?f=88235.294%20mol%5Ctimes%2028%20g%2Fmol%3D2.470588.2%20g%3D2%2C470.588%20kg)
The rate of flow of nitrogen into the reactor is 2,470.588 kg/h.
First, we write the atom with 24 electrons. Atoms are neutral, so their electrons and protons are equal in number. The element with proton number 24 is chromium.
Next, a manganese atom has 25 electrons, so if it forms a cation with a +1 charge, it will have 24 electrons. Similarly, if an iron atom which normally has 26 electrons forms a +2 charge cation, it also has 24 electrons. The three symbols are:
Cr
Mn⁺¹
Fe⁺²
Answer:
Total no. of atoms in 0.25 moles of H2 are 3.01 × 10^23.
Explanation:
Answer:
Calculate the mass percent of a potassium nitrate solution when 15.0 g KNO3 is dissolved in 250 g
of water.
2. Calculate the mass percent of a sodium nitrate solution when 150.0 g NaNO3 is dissolved in 500 mL
of water. Hint: 1 mL water = 1 g water
3. Calculate the weight of table salt needed to make 670 grams of a 4.00% solution.
4. How many grams of solute are in 2,200 grams of a 7.00% solution?
5. How many grams of sodium chloride are needed to prepare 6,000 grams of a 20% solution?
Mass Percent = Grams of Solute
Grams of Solution X 100%
100%
Grams of Solute = Grams of Solution X Mass Percent
= 26.8 grams NaCl
= 670 grams X 4.00%
100%
100%
Grams of Solute = Grams of Solution X Mass Percent
= 154 grams solute
= 2,200 grams X 7.00%
100%
100%
Grams of Solute = Grams of Solution X Mass Percent
= 1,200 grams NaCl
= 6,000 grams X 20.0%
100%
Explanation: