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3 years ago

Which type of bond is formed between atoms of solid gold

Chemistry

2 answers:

goldfiish [28.3K]3 years ago

5 0

Answer:

covalent bonds

Explanation:

maxonik [38]3 years ago

5 0

The type of bond formed is known as a metallic bond

In order to identify the type of bond formed between atoms, you must know the requirements needed for each:

A covalent bond can only have non-metals. In this type of bonding, electrons are shared between atoms.

An ionic bond has both non-metals and metals. In this type of bonding, electrons are transferred. In other words, one atom gives electrons to another atom.

Finally, a metallic bond has only metals. In this type of bonding, electrons are delocalized. Essentially, it means that electrons just float around the metal atoms, and aren't designated to a specific atom. (This quality is the reason why metals are so conductive)

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Good luck :))

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If 14.3 moles of H2O2 is decomposed, how many grams of oxygen gas are produced?

Studentka2010 [4]

The balanced chemical reaction would be as follows:

2H2O2 = 2H2O + O2

We are given the amount of the peroxide that decomposes. Using this as the starting point for the calculations, we can determine the amount of O2 produced. We do as follows:

14.3 mol H2O2 ( 1 mol O2 / 2 mol H2O2 ) = 7.15 mol O2 produced

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2 years ago

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Which noble gas will Selenium try to resemble when it becomes an ION?

lapo4ka [179]

Answer:

Krypton

Explanation:

When Selenium forms an ion, it is trying to become krypton which is a noble gas.

Selenium belongs to the oxygen group on the periodic table. In this group, the atoms prefers to gain two electrons to complete their octet. When selenium gains two electrons, its octet is complete.

This will make the atom resemble krypton on the periodic table of elements.

This structure which is an octet confers a special stability on the element.

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3 years ago

Bronze is an alloy, which is what form of matter?

grandymaker [24]

It is a Compound. have a nice day

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3 years ago

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Hydrogen fuel cells are a promising alternative to gasoline engines in part because they release water instead of carbon dioxide

enot [183]

Answer:

The correct answer is option (B) Two molecules of H2 and a molecule of O2 must collide at one time

Explanation:

2H2(g) + O2(g) → 2 H2O(g)

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Considering the given reaction, for water molecule to be form, two molecules of hydrogen and one molecule of oxygen must collide at the same time. The product obtained from the collision is two molecules of water as steam. 2 H2O(g)

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3 years ago

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combustion analysis of a hydrocarbon produced 33.01g CO2 and 13.51g H2O. Calculate the empirical formula for the hydrocarbon

masya89 [10]

Answer:

$\rm CH_2$ .

Explanation:

Carbon and hydrogen are the only two elements in a hydrocarbon. When a hydrocarbon combusts completely in excess oxygen, the products would be $\rm CO_2$ and $\rm H_2O$ . The $\rm C$ and $\rm H$ would come from the hydrocarbon, while the $\rm O$ atoms would come from oxygen.

Look up the relative atomic mass of these three elements on a modern periodic table:

$\rm C$ : $12.011$ .
$\rm H$ : $1.008$ .
$\rm O$ : $\rm 15.999$ .

Calculate the molar mass of $\rm CO_2$ and $\rm H_2O$ :

$M(\mathrm{CO_2}) = 12.011 + 2 \times 15.999 = 44.009\; \rm g \cdot mol^{-1}$ .

$M(\mathrm{H_2O}) = 2 \times 1.008 + 15.999 = 18.015\; \rm g \cdot mol^{-1}$

Calculate the number of moles of $\rm CO_2$ molecules in $33.01\; \rm g$ of $\rm CO_2\!$ :

$\displaystyle n(\mathrm{CO_2}) = \frac{m(\mathrm{CO_2})}{M(\mathrm{CO2})} = \frac{33.01\; \rm g}{44.009\; \rm g\cdot mol^{-1}} \approx 0.7501\; \rm mol$ .

Similarly, calculate the number of moles of $\rm H_2O$ molecules in $13.51\; \rm g$ of $\rm H_2O\!$ :

$\displaystyle n(\mathrm{H_2O}) = \frac{m(\mathrm{H_2O})}{M(\mathrm{H_2O})} = \frac{13.51\; \rm g}{18.015\; \rm g\cdot mol^{-1}} \approx 0.7499\; \rm mol$ .

Note that there is one carbon atom in every $\rm CO_2$ molecule. Approximately $0.7501\; \rm mol$ of $\rm CO_2\!$ molecules would correspond to the same number of $\rm C$ atoms. That is: $n(\mathrm{C}) \approx 0.7501\; \rm mol$ .

On the other hand, there are two hydrogen atoms in every $\rm H_2O$ molecule. approximately $0.7499\; \rm mol$ of $\rm H_2O$ molecules would correspond to twice as many $\rm H\!$ atoms. That is: $n(\mathrm{H}) \approx 2 \times 0.7499 \; \rm mol\approx 1.500\; \rm mol$ .

The ratio between the two is: $n(\mathrm{C}): n(\mathrm{H}) \approx 1:2$ .

The empirical formula of a compound gives the smallest whole-number ratio between the elements. For this hydrocarbon, the empirical formula would be $\rm CH_2$ .

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3 years ago